How to make a query in access to get InTime and OutTime Between 5:00 am and next day 5:00am?

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I am using MS access 2010.

I need to get the InTime and OutTime between the timing 5am today till 5am tomorrow. Because some employee will come by today morning,say,10:00 am and may leave the office by next day morning 2:00 am. so I need to calculate his/her intime and outtime.

The query used is:

SELECT DateValue(Trans.Dt) AS DateOfAttendance, Format(Min(Trans.Dt) ,"MM/dd/yyyy HH:mm:ss") AS InTime, Format(Max(Trans.Dt),"MM/dd/yyyy HH:mm:ss") AS OutTime, EmpID FROM Trans WHERE (DateValue(Trans.Dt)=date()) GROUP BY DateValue(Trans.Dt),Trans.EmpID;

Thanks in Advance!!!

Posted 5-Sep-14 3:09am

sai sruthi

Updated 8-Sep-14 22:51pm

v3

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Comments

Richard Deeming 5-Sep-14 9:35am

Didn't your colleague already solve this problem yesterday?
http://www.codeproject.com/Messages/4895882/Select-records-between-day-time-and-dayplus-until.aspx[^]

sai sruthi 12-Sep-14 8:27am

The given link has many solutions and the query
WHERE
(DateValue(Trans.Dt) in ('8/25/2014') And Format(Trans.Dt,"Short Time") >= '05:00')
Or
(DateValue(Trans.Dt) in ('8/26/2014') And Format(Trans.Dt,"Short Time") <= '05:00')

is working and it gives output as intime and outtime for 8/25/2014 separately and for 8/26/2014 separately.
But I need for example,
empid=0097 has intime=8/25/2014 10:52:44 and OutTime=8/26/2014 03:15:22
i.e) the employee has come by 25th of august and left by 26th of august.
but the case is that he may have many checkin and checkout for the same day.
the problem is that the query retrieves the last checkout for that day(before 12:00 AM) and the checkin after 12:00 AM as first checkin for next day.

please solve this problem

Thanks in Advance!!!

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Richard MacCutchan · Answer 1 · 2014-09-08T22:58:00

Solution 1

You have been given a link to a solution, please go and try it.

Posted 8-Sep-14 22:58pm

Richard MacCutchan