URI formats are not supported

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I am implementing webservices API. I am sending request in xml form in which some credentials coming from database and on the response of my request I am getting xml form feedback. I am using SOMee server for testing when i am running my program i am getting an error "URI formats are not supported". Please help me to resolve my query. For referenece i am pasting my code.

C#

if (oDataSet.Tables[0].Rows.Count > 0)
        {
            XmlWriter oXmlWriter = XmlWriter.Create("http://impertosolutions.somee.com//MobileAPI_XML//MobileBookingRequest.xml");
            
            oXmlWriter.WriteStartDocument();
            
            oXmlWriter.WriteStartElement("ReprintRequest");

            oXmlWriter.WriteStartElement("UserTrackID");
            oXmlWriter.WriteString(oDataSet.Tables[0].Rows[0]["OrderId"].ToString());

            oXmlWriter.WriteEndElement();

            oXmlWriter.WriteEndDocument();
         
            oXmlWriter.Close();

            XmlDocument oXmlDocument= new XmlDocument();
            oXmlDocument.Load("http://impertosolutions.somee.com//MobileAPI_XML//MobileBookingRequest.xml");
            StringWriter oStringWriter= new StringWriter();
            XmlTextWriter oXmlTextWriter= new XmlTextWriter(oStringWriter);
            oXmlDocument.WriteTo(oXmlTextWriter);
            Response.ContentType="text/xml";
            lstrInput = oXmlDocument.OuterXml;

            lobjServ.REPRINT(lobjSec, lstrInput, ref lstrOutput, ref lstrError);
        }

Posted 2-Apr-15 4:06am

Member 11576179

Updated 3-Apr-15 0:25am

RajeeshMenoth

v3

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Sergey Alexandrovich Kryukov 2-Apr-15 10:17am

How about an example of such URI?
—SA

1 solution

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E.F. Nijboer · Answer 1 · 2015-04-02T04:31:00

Solution 1

If your code litteraly includes the a href then the uri is indeed invalid. Might also be a mistake when creating this question. In that case please edit this question and let me know. I will then remove this answer.

oXmlDocument.Load("<a href="http://impertosolutions.somee.com//MobileAPI_XML//MobileBookingRequest.xml">http://impertosolutions.somee.com//MobileAPI_XML//MobileBookingRequest.xml</a>");

You cannot simply open an URL as if it was a local file. The webserver simply won't accept it. You first need to create the xml (file) and then upload it to the url. Change your code so it writes the xml to an actual file (for example: c:\temp\MobileBookingRequest.xml)

Then after you are done and called xmlWriter.Close(); try this:

WebClient client = new WebClient();
//client.Credentials = new NetworkCredential("username", "password");
client.UploadFile("http://impertosolutions.somee.com/MobileAPI_XML/MobileBookingRequest.xml", "c:\temp\MobileBookingRequest.xml");

Good luck!

Posted 2-Apr-15 4:31am

E.F. Nijboer

Updated 2-Apr-15 23:52pm

v2

Comments

Member 11576179 3-Apr-15 4:40am

string orderid = "";
// int number = Convert.ToInt32(txtcontactnumber.Text.Trim());
//string compa= "Unique Order ID";

oDataSet = new DataSet();
oCommonBal.InputType = "Build_OrderId";
oDataSet = oCommonDal.GetRechargeDetail(oCommonBal);
if (oDataSet.Tables[0].Rows.Count > 0)
{
orderid = oDataSet.Tables[0].Rows[0]["OrderId"].ToString();
}
oCommonBal.InputType = "Insert";
oCommonBal.Contact_Number = Convert.ToInt64(txtcontactnumber.Text.Trim());
oCommonBal.OrderID = orderid;
oCommonBal.CompanyName = ddloperator.SelectedValue.ToString().Trim();
oCommonBal.Amount = Convert.ToInt32(txtamount.Text.Trim());
oCommonBal.ItemDesc = txtItemDesc.Text.Trim();
int iRowaffected = oCommonDal.InsertRechargeDetail(oCommonBal);

XmlWriter xmlWriter = XmlWriter.Create("http://abc.com/MobileAPI_XML/MobileBookingRequest.xml");

xmlWriter.WriteStartDocument();
xmlWriter.WriteStartElement("MobileBookingRequest");

xmlWriter.WriteStartElement("UsertrackId");
xmlWriter.WriteString(oCommonBal.OrderID);
xmlWriter.WriteEndElement();

xmlWriter.WriteStartElement("Itemid");
xmlWriter.WriteString(oCommonBal.CompanyName);
xmlWriter.WriteEndElement();

xmlWriter.WriteStartElement("ItemDesc");
xmlWriter.WriteString(oCommonBal.ItemDesc);
xmlWriter.WriteEndElement();

xmlWriter.WriteStartElement("MobileNo");
xmlWriter.WriteString(oCommonBal.Contact_Number.ToString());
xmlWriter.WriteEndElement();

xmlWriter.WriteStartElement("Amount");
xmlWriter.WriteString(oCommonBal.Amount.ToString());
xmlWriter.WriteEndElement();

xmlWriter.WriteEndDocument();

xmlWriter.Close();

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load("http://abc.com/MobileAPI_XML/MobileBookingRequest.xml");
StringWriter sw = new StringWriter();
XmlTextWriter xw = new XmlTextWriter(sw);
xmlDoc.WriteTo(xw);
//return sw.ToString();
Response.ContentType = "text/xml";
lstrInput = xmlDoc.OuterXml;

Member 11576179 3-Apr-15 4:41am

This is my actual code. Please help me ,where i am going wrong in my code.

E.F. Nijboer 3-Apr-15 5:53am

I added some additional info and example code to my answer.