C# random numbers in loop

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I want to random number in loop with 8 digits.
for example:
for (i=0;i<10;i++)
{
//here I want to random number like this :35467382
}

How can I do it?

Posted 15-Oct-13 22:05pm

Member 10304617

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3 solutions

Solution 1

Use the Random class eight times to give you a number between 0 and 9!

Posted 15-Oct-13 22:12pm

Rob Philpott

Solution 3

Here is the below code to generate 8 digit random number code.

C#

Random random = new Random();
            char[] ch = "0123456789".ToCharArray() ;

            for (int j = 0; j < 10; j++)
            {
                string random_number_string = "";
                for (int i = 0;random_number_string.Length!=8; i++)
                {
                    int x = random.Next(0, ch.Length);
                    random_number_string += ch.GetValue(x).ToString();
                    
                }
                Console.WriteLine(random_number_string);
                
            }

Posted 15-Oct-13 22:40pm

tarunsitlani

Comments

Member 10304617 16-Oct-13 4:49am

Thanks you!

Ron23111 25-Aug-18 20:35pm

And if you also want it each number to star with 18 like 18126342, 18436253, 18627536 etc..

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OriginalGriff · Accepted Answer · 2013-10-15T22:15:00

Solution 2

Try:

C#

private Random rand = new Random();

private void DoRand()
    {
    for (int i = 0; i < 10; i++)
        {
        int randNo = rand.Next(10000000, 100000000);
        Console.WriteLine(randNo);
        }
    }

The lower bound excludes numbers with leading zeros, the upper bound limits it to 10000000..99999999 inclusive.

Posted 15-Oct-13 22:15pm

OriginalGriff

Comments

Member 10304617 16-Oct-13 4:32am

Thanks!!

OriginalGriff 16-Oct-13 4:45am

You're welcome!