checkbox is not check in one click and not uncheck in one click

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hello ,I'm using this code in the checkbox but after use this,my checkbox is not work properly like. Like it is not checked in one click and after checked it is not unchecked in one click.
please help me.............

C#

private void checkBox4_CheckedChanged(object sender, EventArgs e)
        {
            
 if (checkBox4.Checked == true)
            {
                panel1.Show();
                radioButton1.Show();
                radioButton2.Show();
                radioButton3.Show();
                radioButton9.Show();
                radioButton8.Show();

}
}

Posted 24-Mar-11 20:33pm

situ21

Updated 24-Mar-11 20:48pm

v3

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Prerak Patel 25-Mar-11 2:35am

Use <pre> tags for code

situ21 25-Mar-11 2:42am

sir,tell me the solution of my problem

R. Erasmus 25-Mar-11 3:35am

indent you're code to make it look appealing.

4 solutions

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Wendelius · Answer 1 · 2011-03-24T20:42:00

Solution 1

Do you mean you it also has a state where a 'block' is shown inside the checkbox. If that's the case change the ThreeState property to false.

Also you don't have to set the Checked property to true if it already is true so you can remove:

checkBox4.Checked=true;

from inside the If

Posted 24-Mar-11 20:42pm

Wendelius

Sergey Alexandrovich Kryukov · Answer 2 · 2011-03-25T06:39:00

Solution 4

You need to put radio buttons in a group box. You also should not Show/Hide then. You have their parent panel. Use MyPanel.Visible = some_boolean;. In this way, you show/hide panel with all its children, and keep children visible all the time.

—SA

Posted 25-Mar-11 6:39am

Sergey Alexandrovich Kryukov

Tiwari Avinash · Answer 3 · 2011-03-24T20:49:00

C#

private void checkBox4_CheckedChanged(object sender, EventArgs e)
        {

 if (checkBox4.Checked == true)
            {
                panel1.Show();
                radioButton1.Show();
                radioButton2.Show();
                radioButton3.Show();
                radioButton9.Show();
                radioButton8.Show();
                
                //checkBox4.Checked=true; remove this line
}
}

after checking the condition with true you are again defining the state of checkbox to true.. seems to be the problem try it out with checked state as false or no need to declare again state of checkbox..
happy coding:-)

fcronin · Answer 4 · 2011-03-25T12:48:00

Solution 5

If you're trying to show the contents of panel1 when the box is checked, the following could work...

C#

private void checkBox4_CheckedChanged(object sender, EventArgs e)
{
   panel1.Visible = checkBox4.Checked;
}

Regards,
Frank

Posted 25-Mar-11 12:48pm

fcronin