a question about string in C++

Question

1.00/5 (1 vote)

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string s="123456";
I can not see the value of s[0] in the watch table when I debug my code.
Instead, it shows me"CXX0058 :error:overload operator not found"
shouldn't s[0] be '1'?

Posted 21-Apr-11 2:24am

solesonglei

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3 solutions

Solution 1

You can try memory window. Put there pointer to string buffer.

Posted 21-Apr-11 2:33am

Kozlov_Sergey

Solution 4

you have to create a string buffer
just like
StringBuffer sb=new StringBuffer(s);

Posted 21-Apr-11 2:36am

Himansu sekhar bal

Comments

Nish Nishant 21-Apr-11 8:40am

OP's talking about native C++ collections.

Himansu sekhar bal 21-Apr-11 8:48am

ok,you are correct

Nish Nishant 21-Apr-11 8:51am

I reckon I am! :-)

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Nish Nishant · Accepted Answer · 2011-04-21T02:34:00

Solution 2

It's due to a debugger restriction with overloaded operators. You'll find the same with other types like vector<>.

Posted 21-Apr-11 2:34am

Nish Nishant

Comments

solesonglei 21-Apr-11 9:06am

thx.

Nish Nishant 21-Apr-11 9:14am

You are welcome.

E.F. Nijboer 21-Apr-11 11:25am

Nice. Learned something :-)

Sergey Alexandrovich Kryukov 21-Apr-11 14:57pm

Good, a 5.
--SA