Hello try this code. If you find any easy solution than of mine then please reply me. Thanks...
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
open.Filter = "Image Files(*.jpeg;*.bmp;*.png;*.jpg)|*.jpeg;*.bmp;*.png;*.jpg";
if (open.ShowDialog() == DialogResult.OK)
{
textBox1.Text = open.FileName;
}
cn.Open();
string image = textBox1.Text;
Bitmap bmp = new Bitmap(image);
FileStream fs = new FileStream(image, FileMode.Open, FileAccess.Read);
byte[] bimage = new byte[fs.Length];
fs.Read(bimage, 0, Convert.ToInt32(fs.Length));
fs.Close();
SqlCommand cmd = new SqlCommand("insert into ImageUpload(imgdata) values(@imgdata)",cn);
cmd.Parameters.AddWithValue("@imgdata",SqlDbType.Image).Value=bimage;
cmd.ExecuteNonQuery();
cn.Close();
}