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Sorry David,
It's not what I meant.
Question was about the HPC cluster.
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Perhaps this instead?
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
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Yes. If you have some expertise, please share.
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I don't. I was just trying to clarify (for others) exactly what you were asking.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
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Cause you have to reprogram a lot of code with the CUDA, and our program is already parallelized with the OpenMP.
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Hi,
We have lot of modules to handle with for big applications. So, how will we understand the dependencies?I mean if to compile program using make file, how can I know which all modules to compile with?
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Does your IDE support compiling and linking?
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
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You are (or, at least, should be) the author of the makefile, hence it is up to you to specify the correct dependencies in it.
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The overriding concept of makefiles is the ability to specify the dependencies in a simple tree. But since you are the one who knows which module(s) depend on which, you are the person who will need to create the tree.
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Hello, there is a pseudocode for recursive radix 2 DIT Fast Fourier Transform(page 11,12) at this link.
I have written a code in c++ which does the same, but it doesn't work properly.
For example when I take 1024 datapoints of sin(0.1*x) where x={0,1,...1023}, I get this.
Reverse transform inserted for this gives initial function multiplied by 1024, so it works.
What could be wrong? I tried with value dir and dir/2 inside "Shift" function too.
Here is the code:
Notation: E2-even part, E3-odd part
I work without complex numbers library, so there are both "_re" and "_im" tables.
void FFT(double *tab_re, double *tab_im, double *results_re, double *results_im, int n, int dir) {
if(n==1)
{results_re[0]=tab_re[0]; results_im[0]=tab_im[0]; return;}
int nh=n/2;
double *E2_re=new double [nh];
double *E3_re=new double [nh];
double *E2_im=new double [nh];
double *E3_im=new double [nh];
double *F2_re=new double [nh];
double *F3_re=new double [nh];
double *F2_im=new double [nh];
double *F3_im=new double [nh];
for(int k=0;k<nh;++k) {E2_re[k]=tab_re[2*k];
E2_im[k]=tab_im[2*k];
E3_re[k]=tab_re[2*k+1];
E3_im[k]=tab_im[2*k+1];}
FFT(E2_re,E2_im,F2_re,F2_im,nh,dir);
FFT(E3_re,E3_im,F3_re,F3_im,nh,dir);
Shift(F3_re,F3_im,nh,dir);
for(int k=0;k<nh;++k)
{
results_re[k]=F2_re[k]+F3_re[k];
results_im[k]=F2_im[k]+F3_im[k];
results_re[k+nh]=F2_re[k]-F3_re[k];
results_im[k+nh]=F2_im[k]-F3_im[k];}}
void Shift(double *tab_re, double *tab_im, int n, int v)
{double re,im;
double pi=3.14159265359;
double arg;
for(int i=0;i<n;++i)
{re=tab_re[i];
im=tab_im[i];
arg=v*2.0*pi*i/n;
tab_re[i]=re*cos(arg)-im*sin(arg);
tab_im[i]=re*sin(arg)+im*cos(arg);}}
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If you get the original function back after the reverse, you have probably coded the transform correctly.
The problem is likely to be that your sampling rate is not a multiple of the basic frequency of sin(0.1*x). This means that you get a large FFT component close to the frequency, but you also get "noise" throughout the range, due to the fact that the residues do not cancel out.
I would try taking an FFT of sin(x), sin(2*x), etc., and see if these functions give the expected values.
Freedom is the freedom to say that two plus two make four. If that is granted, all else follows.
-- 6079 Smith W.
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Thank You for the hint. I have tried with sin(nx), sin(2pi*x/n) and sin(2pi*x*n) too, but results were similar.
The most promising result was for the option with sin(2pi*x*n): here is a result with n=10. Values for x>270 are 0.
I used decimation in frequency FFT instead of decimation in time version, but it still doesn't show good values.
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You lost me with your translation of the code .. page 11 & 12 have the exp function which doesn't appear in your code?
In vino veritas
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The exp function is inside function called "Shift".
As I wrote earlier, I don't use complex numbers library, so there are both tables for real and imagery parts. I used this relation: exp(i*phi)=cos(phi)+i*sin(phi).
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Bonjour, //hi
essayez avec : //try with
arg=v*pi*i/n;
k++); //two time
i++);
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Hello, I do not want to use an MDI app to create new documents of the same kind, like in text processors. Instead I want to be able to open different child windows from the menu. The menu handling is clear. When I go and create a new form with controls in the resources/dialog editor, how can I connect them to what I see in the client area of the child ? The classic kind of business software, you know. A user can open a customer window, then a payment window, a child for envoices, for banking, statics and so on. Normal dialog windows do not fill the client area, they are on top of all. That is not what I am going for. Thank You.
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Hallo Victor,
yes I just did. That issue is different. Mine is about connecting the window resource to the canvas of the app. That one from the painter, where all controls are placed.
Thank You
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Member 11883602 wrote: That issue is different. Mine is about connecting the window resource to the canvas of the app. That one from the painter, where all controls are placed.
And how would it differ from what CMultiDocTemplate represets?
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Hello. I got it now. To occupy an SDI/MDI with a formview resource template there is one detail in the project assistant. At the last page one can fill in from what the view derives. The preset is CView, but you must change it to CFormView. That was all. Well, I would have liked to make it an existing project, but this is ok, too. Thank You.
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In my MFC application, I am doing a custom drawing in my dialog class OnPaint(). I have also created a few controls in dialog template. I have also resized and repositioned some of the controls in the dialog code. When I run my application, the controls are flickering.
Please suggest me how to avoid this?
BOOL CFP::OnInitDialog()
{
CDC *pDC = GetDC(); //Get DC for Dialog's Client Area
pDCTmp->CreateCompatibleDC(pDC); //Create Compatible DC(pDCTmp) for Dialog's Client Area(pDC)
//pDCTmp is a member Variable
pBgBitmap->CreateCompatibleBitmap (pDC, 800, 640 ); //Create Compatible Bitmap(pBgBitmap) for Dialog's Client Area(pDC)
//pBgBitmap->LoadBitmap(IDB_FORESTIMAGE);
pDCTmp->SelectObject(pBgBitmap);
ReleaseDC(pDC);
}
void CFacePlate::OnPaint()
{
CPaintDC dc(this); // device context for painting
// TODO: Add your message handler code here
CRect rect;
rect = rScreen; //rScreen is Client rect
pDCTmp->FillRect(rect,&CBrush(RGB(152, 185, 192))); //pDCTmp member variable is used to draw
.
.
.
.
//Custom drawings using the pDCTmp
}
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I see nothing in your code snippet that causes flickering.
How did you implement the "Custom drawings"?
When does the flickering happen? While resizing only?
Which controls flicker?
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