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QuestionBoost Spirit: Parse an int into a string. Pin
Maximilien21-Feb-17 2:54
Maximilien21-Feb-17 2:54 
I am trying to parse an expression like this: 
F( 1, 2, 3)

and extract 1, 2 and 3 as a strings.

My test grammar and program parse properly, but the output is not "nice",

In the start, limit and increment variable contain strings like "\x1", "\x2" and "\x3"

This is part of my grammar. (the pre tag does not work "good" here)

I also tried to read the numerical value as an int and use a boost::variant to hold either an int or std:wstring, but that did not work.

Any thoughts, hints or tips ?

Thanks.

More friendly code here http://pastebin.com/2mmK9gns
struct RangeResult
{
    std::wstring start;
    std::wstring limit;
    std::wstring increment;
};

BOOST_FUSION_ADAPT_STRUCT(
    RangeGrammar::RangeResult,
    (std::wstring, start)
    (std::wstring, limit)
    (std::wstring, increment)
)

template <typename Iterator>
struct range_parser : boost::spirit::qi::grammar<Iterator, RangeResult(), iso8859_1::space_type>
{
    range_parser() : range_parser::base_type(start)
    {
            using qi::lit;
            using qi::lexeme;
            using qi::int_;
            using iso8859_1::char_;
            using iso8859_1::digit;

            variable_string %= lexeme["$(" >> +(char_ - ")") >> ")"];

            node = (int_ | variable_string);

            start %=
                lit("_RANGE")

<blockquote class="quote">
  <blockquote class="quote">
    '('
    node >> ',' >> node >> ',' >> node
    ")_"
                    ;
  </blockquote>
</blockquote>

            debug(variable_string);
            debug(start);

        }

        qi::rule<Iterator, std::wstring(), iso8859_1::space_type> variable_string;
        qi::rule<Iterator, std::wstring(), iso8859_1::space_type> node;
        qi::rule<Iterator, RangeResult(), iso8859_1::space_type> start;

};

My test program:
C++
void TestRangeGrammar()
{
    using boost::spirit::iso8859_1::space;
    typedef std::wstring::const_iterator iterator_type;
    typedef RangeGrammar::range_parser<iterator_type> range_parser;

<pre>
range_parser grammar; // Our grammar

std::array< std::wstring, 1 > testStrings =
{{
        _TEXT("_RANGE(1, 2, 3 )_")
}};

for (auto str : testStrings)

{
std::wstring::const_iterator iter = str.begin();
std::wstring::const_iterator end = str.end();

RangeGrammar::RangeResult emp;

bool r = phrase_parse(iter, end, grammar, space, emp);
if (r)
{
std::wcout << _TEXT("-------------------------\n");
std::wcout << _TEXT("Range Parsing succeeded\n");
std::wcout << _TEXT("Start: ") << emp.start << std::endl;
std::wcout << _TEXT("Start: ") << emp.limit << std::endl;
std::wcout << _TEXT("Start: ") << emp.increment << std::endl;
std::wcout << _TEXT("\n-------------------------\n");
}
else
{
std::wcout << _TEXT("-------------------------\n");
std::wcout << _TEXT("Range Parsing failed\n");
std::wcout << str << std::endl;
std::wcout << _TEXT("-------------------------\n");
}
}
}
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