Welcome to the Lounge

glennPattonWork wrote:

Guess what my companies favoured Goggle search is this PM

1. If the year is set to '00' in PHP, it apparently doesn't mean '0000', instead it is short hand for '2000'. So '00-00-00' means The year '2000', the month '00', and the day '00'.
2. Okay, but the month can't be zero! '00' means you have to subtract one from the year, which makes the year '1999', and the month '12'. That gets us to '1999-12-00'
3. Drat, day is also zero! Time to subtract a day from the month, '1999-11-30'

class Integer
{
    public int Value { get; set; }

    public Integer() =>
        Value = 0;

    public Integer(int number) =>
        Value = number;

    public static Integer operator +(Integer d1, Integer d2) =>
        new Integer(d1.Value + d2.Value);

    public static string operator +(string s, Integer d) =>
        s + d.Value;

    public static string operator +(Integer d, string s) =>
        d.Value + s;

    public static Integer operator -(Integer d1, Integer d2) =>
        new Integer(d1.Value - d2.Value);

    public static Integer operator -(Integer d, string s) =>
        new Integer(d.Value - int.Parse(s));

    public static Integer operator -(string s, Integer d) =>
        new Integer(int.Parse(s) - d.Value);

    public static implicit operator int(Integer d) =>
        d.Value;

    public static implicit operator Integer(int d) =>
        new Integer(d);
}

static void Main(string[] args)
{
    string x = "5";
    Integer y = 3;
    Integer result1 = x + y - y;
    Integer result2 = x - y + y;
    Console.WriteLine($"Result1: {result1.Value}\nResult2: {result2.Value}");
    Console.ReadKey();
}

CodeWraith wrote:

What would you prefer?

Bastard Programmer from Hell
If you can't read my code, try converting it here[^]
"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.

CodeWraith wrote:

And what part of this subtle hint not to update install Java do you not understand?