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Try giving /FORCE:MULTIPLE in the properties in
Project Properties -> Configuration Properties -> Linker -> Command Line -> Additional Options.
«_Superman_»
I love work. It gives me something to do between weekends.
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I am attempting to understand how to use the class CToolBar. Therefore, I wrote some sample
code that is suppose to create a tool bar. However, the tool bar is not being displayed. The
definition of the tool bar is in my class CMainWindow and is defined as follows:
CToolBar toolBar;
Here is the code that I use to create the tool bar:
<br />
BOOL status1 = toolBar.Create( this );<br />
BOOL status2 = toolBar.LoadToolBar( IDR_TOOLBAR );<br />
toolBar.SetButtonStyle( 0, TBBS_CHECKBOX );<br />
toolBar.SetButtonStyle( 1, TBBS_CHECKBOX );<br />
toolBar.SetButtonStyle( 2, TBBS_CHECKBOX );<br />
toolBar.SetButtonStyle( 3, TBBS_CHECKBOX );<br />
toolBar.SetButtonStyle( 4, TBBS_CHECKBOX );<br />
toolBar.SetButtonStyle( 5, TBBS_CHECKBOX );<br />
<br />
const UINT idArray[] = {<br />
IDM_LINES, IDM_RECTANGLES, IDM_ELLIPSES,<br />
IDM_ENLARGE, IDM_ORG, IDM_RESET<br />
};<br />
<br />
toolBar.SetButtons( idArray, 6 );<br />
toolBar.ShowWindow( SW_SHOW );<br />
toolBar.SetSizes( CSize(48,42 ), CSize( 40, 19 ) );
The return value from Create is 1 and the return value from LoadToolBar is 1. The return value from SetButtons is 1. The return value from ShowWindow is 16. I am interpreting these return values to mean that all went well. However, the tool bar is not being displayed. I am hoping that somebody out there can tell me what I am doing wrong.
Thanks
Bob
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hi i have a toolbar with buttons added
btnBookmark.idCommand = idCommand;
btnBookmark.fsState = TBSTATE_ENABLED;
btnBookmark.fsStyle = BTNS_BUTTON | BTNS_AUTOSIZE| BTNS_SHOWTEXT;// | BTNS_DROPDOWN;//| ;
btnBookmark.dwData = 0;
btnBookmark.iString = (INT_PTR)cstrKeyName.GetBuffer();
btnBookmark.iBitmap = -2;
but the text on the toolbar buttons is a bit high its not vertically centere
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Hi,
I'm working on a program that reads linear equations from a file such as those:
3x+2y-2.5z=9
-2x+9y+12z=23.4
4.2x-7y+9.6z=45.3
The file is supposed to contain n equations with n variables which I would read into a 2d dynamic array of doubles and then I'm supposed to solve the resulting matrix using Gauss's method. I've already implemented Gauss's method but I can't figure out when reading from file how to get only the numbers and the signs for example from the above equations I'm supposed to have the following in the array:
[+3][+2][-2.5]
[-2][+9][+12]
[+4.2][-7][+9.6]
I need the numbers after the equal sign to be stored in a separate n sized array as well.
If anyone has any ideas I'd really appreciate it 
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here i have a rough idea.
Omar Al Qady wrote: 3x+2y-2.5z=9-2x+9y+12z=23.44.2x-7y+9.6z=45.3
fscanf(fp,"%fx%fy%fz=5f",el1,el2,el3,el4);
should fetch you the required values into el1....el4.
try it out if it does not work we shall find out some other way.
good luck.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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The problem is that the variables aren't always x,y,z because the program should solve n equations with n variables, so they can be more than 3 or less, so I can't assume when reading the data it's only three variables.
I thought about something but I just can't implement, if I can read double by double into the array until I reach the equal sign then the double after is read into a different n sized array for the solutions, and when a new line is started I'd repeat the process in the next row of the 2d array.
I don't know if what I said above is even possible but if you can help me in implementing it I'd be grateful
Thanks for your reply and thanks in advance for any additional help you can give
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if i understood your problem correctly,
then open the src file in read mode,
open another dest file in write mode,
copy character by character from src file to dest file.
if any alphabet is read, then write some standard character like ':' or any other char which is not in your expressions.
for example, 3x-2y+7z-3q=2.5 will become 3:-2:+7:-3:=2.5
then do something like
fscanf("%f:",&el1);
still some more logics we may have to implement like finding size of the 2d array etc.
we can work around them subsequently if u have understood till here.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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I don't think so.
First you don't need to create a file in order to read and parse an existing file.
Second, there is no guarantee the variables are ordered the same in every line and/or a coefficient of zero gets mentioned at all, so one really has to check the variable names.
All it takes is reading the characters of a line, then parse it into numbers, identifiers and operators.
Luc Pattyn [Forum Guidelines] [My Articles]
DISCLAIMER: this message may have been modified by others; it may no longer reflect what I intended, and may contain bad advice; use at your own risk and with extreme care.
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Luc Pattyn wrote: there is no guarantee the variables are ordered the same in every line
yes it is a valid point. even iam thinking in that perspective.i assumed the same sequence of variables while posting.
let the op confirm this point, i.e. if the same sequence is guarenteed or not..
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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No the sequence is not constant and there might be coefficients of 0 which would the variable would not be at all present in the line.
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fine then,
i will also work aroundit. as of now, do as luc pattyn suggested.
if you get the solution please specify it here.
otherwise i shall attempt it on monday.
all the best.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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OK then, thank you all for your help and I'll post here if I get it done
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Hmm, How about a RegExp? You could scrub data into a tonenized string then convert it to an array.
There is an open source mathematics program called 'sage', I would look atthe aproach they are implimenting. Also, you might find other good ideas by searching for OpenML. There are many examples supported by many frameworks.
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I'll look into the source of 'sage' then and see if it's of any help.
The other things you mentioned I'm afraid I don't understand as I am not a very advanced programmer (yet I hope ).
Thanks for replying
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hi,
i have a small idea that, based on the ascii value you can separte the number,x,y,z and = sign.For x,y,z you just read each character and check with in the range(ie 120,121,122,61 for x,y,z,= respectively) and you can use isalpha() for whether the reading data is albhapet or numeric.
regards,
Suthakar
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So maybe I'd read each line into a string, and then go through it char by char checking for letters and = and if not I'd store in the 2d double array and after I find a letter I move to the next column, and so on till the = and store what's after it in the solutions array. I'm getting a vague idea now of how to do this, but are the signs and decimal points also readable and convertible in the same way? For example when reading -2.9 , the - & . wouldn't fall in the range for the letters and the = but can I convert them along with the numbers into a double??
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yes, that is about right, except you are not sure the variables will appear in the same order every time (one even could be omitted when its coefficient happens to be zero). So you must parse the line into numbers, identifier names and operators; then keep an array of known identifiers (=variable names) which leads you to the right column in the 2D matrix.
Luc Pattyn [Forum Guidelines] [My Articles]
DISCLAIMER: this message may have been modified by others; it may no longer reflect what I intended, and may contain bad advice; use at your own risk and with extreme care.
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I was just thinking about what would happen if a coefficient is zero and I just freaked out and thought I'd skip it before your reply  But I'll try your way and see how it goes
Thanks a lot
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First read the file one line at a time.
You could use ifstream::getline[^] for this.
Then you could use the strtok_s function[^] to separate the coefficients.
«_Superman_»
I love work. It gives me something to do between weekends.
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Yes I think I'll try getline() and save each line into a string in a string array, and then parse it like I was advised to do above and save the coefficients in the 2d array while checking for variable in the variable array each time. I think this would be the way to go
Thanks for replying
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Oh yeah, forgot to mention another idea. Create a Red / Black tree from the code. Look at examples for expanding lambda expressions.
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I don't know about this either, so I'll try working with the hints and ideas from above and if it doesn't work out I'll research this and work on it
Thanks for your ideas
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hope your problem is solved.
i did some paperwork onit yesterday and got some ideas.
do you require any more discussion on that today?
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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Actually I was very busy yesterday, so I didn't have time to implement the ideas that I got from the discussion here yet but I'll start working on it today and let you know how it works out. Post your ideas anyway they might help me now I need all the help I can get
Thank you for taking the time to think about the problem
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so, kindly confirm these points for me as per my understanding of the problem.
1. the coefficients may be 0 means, one of the variables may be absent in the expression.
2. the sequence of the variables may change.
3. Will a variable be only 1 character or may be more?
4. what will be the maximum n? (size of expression/number of expressions)
because,
the solution i have sketched are dependant onthese inputs.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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