What is the error in my below code?.I'm getting error on compilation.

Question

1.00/5 (2 votes)

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C++

#include <stdio.h>
#include <string.h>

typedef struct
{
     int id;
     char name[30];
     float percentage;
}status, *var1;

int main()
{

status data;
var1=&data;
strcpy(var1->name,"HelloWorld");
var1->id=100;
var1->percentage=200;
printf("\nEmployee Name : %s\n", var1->name);
printf("\nEmployee ID : %d\n", var1->id);
printf("\nEmployee percentage : %f\n", var1->percentage);
return 0;
}

[edit]Code block added - OriginalGriff[/edit]

Posted 16-Jun-15 3:46am

Member 11372005

Updated 16-Jun-15 4:25am

OriginalGriff

v3

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Comments

Mathew Soji 16-Jun-15 10:27am

What is the compilation error you are getting?

Member 11372005 16-Jun-15 11:16am

i'm getting below error while trying to complie:

gcc -o struct struct.c
struct.c: In function ‘main’:
struct.c:15:5: error: expected identifier or ‘(’ before ‘=’ token
var1=&data;
^
struct.c:16:8: error: expected expression before ‘var1’
strcpy(var1->name,"HelloWorld");
^
struct.c:16:8: error: too few arguments to function ‘strcpy’
struct.c:17:5: error: expected identifier or ‘(’ before ‘->’ token
var1->id=100;
^
struct.c:18:5: error: expected identifier or ‘(’ before ‘->’ token
var1->percentage=200;
^
struct.c:20:34: error: expected expression before ‘var1’
printf("\nEmployee Name : %s\n", var1->name);
^
struct.c:21:32: error: expected expression before ‘var1’
printf("\nEmployee ID : %d\n", var1->id);
^
struct.c:22:40: error: expected expression before ‘var1’
printf("\nEmployee percentage : %f\n", var1->percentage);
^

Richard MacCutchan 16-Jun-15 12:42pm

Why are you using var1, when you already created the structure with the name data? Just remove the line var1=&data;, and replace all var1-> with data. .

OriginalGriff 16-Jun-15 13:36pm

I'm guessing homework and he's supposed to use a pointer.

Member 11372005 17-Jun-15 9:44am

yes i want to assign values to the members of the structure using arrow operator, not using a dot operator.

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OriginalGriff · Answer 1 · 2015-06-16T04:29:00

Solution 1

It helps if you tell us the error message! But...
Change this:

C++

typedef struct
{
     int id;
     char name[30];
     float percentage;
}status, *var1;

To this:

C++

typedef struct
{
     int id;
     char name[30];
     float percentage;
}status;
status *var1;

Posted 16-Jun-15 4:29am

OriginalGriff

Comments

Member 11372005 16-Jun-15 11:13am

I'm getting below error while trying to compile

gcc -o struct struct.c
struct.c: In function ‘main’:
struct.c:15:5: error: expected identifier or ‘(’ before ‘=’ token
var1=&data;
^
struct.c:16:8: error: expected expression before ‘var1’
strcpy(var1->name,"kodiak");
^
struct.c:16:8: error: too few arguments to function ‘strcpy’
struct.c:17:5: error: expected identifier or ‘(’ before ‘->’ token
var1->id=100;
^
struct.c:18:5: error: expected identifier or ‘(’ before ‘->’ token
var1->percentage=200;
^
struct.c:20:34: error: expected expression before ‘var1’
printf("\nEmployee Name : %s\n", var1->name);
^
struct.c:21:32: error: expected expression before ‘var1’
printf("\nEmployee ID : %d\n", var1->id);
^
struct.c:22:40: error: expected expression before ‘var1’
printf("\nEmployee percentage : %f\n", var1->percentage);

OriginalGriff 16-Jun-15 11:26am

And if you change it as above?