How to get the source path while copying a file from one directory to another in minifilter

Question

1.00/5 (1 vote)

See more:

Hello,

I am new in windows driver development. I want to track the source path from where the file is copied to some other directory. I want to do that by using minifilters. Can anyone help me or give me some suggestion how to do that. If someone can provide source code for that than it would be very helpful for me.
Help me as soon as you can do please.
Thanks in advance.

Posted 15-Jul-15 19:39pm

Nishant Varshney

Add a Solution

Comments

Stefan_Lang 16-Jul-15 3:02am

What have you tried? What, exactly, do you need help with? I have no idea at all about minifilters, but it took me less than a minute to dig up this documentation:
https://msdn.microsoft.com/en-us/library/windows/hardware/ff540402%28v=vs.85%29.aspx

Have you read it? Do you need more explanations? WHy don't you go search for already available documentation and code on the web?

Wshwilfried 22-Jul-15 5:09am

I Will suggest you find the IRPs that get sent for the operation you desire to track. There are lots of tutorials here at code project and Google, start from there and once you have tried something i'm sure you get more help.

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)