whats wrong with this program? :"(

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C++

#include<stdio.h>
void main()
    {
    int t,u[5],a[5],i,s;
    printf("enter a value of t");
    scanf("%d",&t);
    printf("enter values of u and a");
    for (i=0;i&lt;5;i++)
        {
        scanf("%d",&u[i]);
        scanf("%d",a[i]);
        s=u[i]*t+1/2 a[i]*t*t;
        printf("value of u is %d \n value of a is %d \n value of t is %d \n value of s is %d \n,u[i],a[i],t,s);
        }
    }
    }

apparently.. when i try to compile this program.. all i get in return is "non function call"... or "statement missing". please help asap.

Posted 27-Sep-15 7:27am

Member 12015032

Updated 27-Sep-15 8:18am

Patrice T

v4

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Member 12015032 27-Sep-15 13:30pm

apparently.. when i try to compile this program.. all i get in return is "non function call"... or "statement missing". please help asap.

PIEBALDconsult 27-Sep-15 13:35pm

Which line?

PIEBALDconsult 27-Sep-15 13:36pm

It appears you are missing a quote (") in your last printf.

Philippe Mori 28-Sep-15 22:51pm

Also for one scanf, then argument are incorrect.

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Patrice T · Answer 1 · 2015-09-27T08:24:00

C++

#include<stdio.h>
void main()
    {
    int t,u[5],a[5],i,s;
    printf("enter a value of t");
    scanf("%d",&t);
    printf("enter values of u and a");
    for (i=0;i<5;i++)
        {
        scanf("%d",&u[i]);
        scanf("%d",a[i]);
        s=u[i]*t+1/2 a[i]*t*t;
        printf("value of u is %d \n value of a is %d \n value of t is %d \n value of s is %d \n", u[i], a[i], t, s);
        }
    }</stdio.h>

A quote was missing in printf and I removed a } at the end.
Compiler should be happier now.

I recommend a professional text editor, syntax coloring would have show the first problem and parenthesis matching would have spot the second.