error while inserting 09 in ArrayList add()?

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hello
i have an error while trying to insert 09 in my ArrayList's add method how to resolve it
when i google for it its give me solution like its a octal no and i need to chage this to decimal no
how do i do this please any one help me ...

Java

import java.util.*;
class MyArrayList{
   public static void main(String args[]){
        ArrayList al=new ArrayList();
        al.add(new Integer(09));
        System.out.println(al);
   }
}

<br />
output:MyArrayList.java:5:error integer too large:09<br />

Posted 10-Oct-15 2:05am

jagdish vaghela

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CPallini · Accepted Answer · 2015-10-10T02:37:00

Solution 1

As have been already told to you, integer literals starting with zero are considered having octal base (and, you know, allowed digit of octal base are {0,1,2,3,4,5,6,7}). If you need to add the decimal 9 to the ArrayList then you have to remove the heading '0', that is change from

Quote:
al.add(new Integer(09));

to

Java

al.add(new Integer(9));

Posted 10-Oct-15 2:37am

CPallini

Updated 10-Oct-15 9:38am

v2

Comments

Patrice T 10-Oct-15 13:05pm

+5{0,2,3,4,5,6,7} is missing 1 :)

CPallini 10-Oct-15 15:39pm

Thank you very much. Fixed now.

jagdish vaghela 11-Oct-15 9:14am

This method is also i know but there is any solutions for do such this type of operation

CPallini 11-Oct-15 10:04am

Solution to what? If 09 is meant to be an octal literal then it is wrong. If it is meant to be a decimal literal then write it properly (that is 9). If ti comes from a string the use the parseInt method to convert directly the string to integer.