Select Only 1 Record From Duplicate Records + Non-Duplicate Records In SQL Server

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hi all,

I have a table in SQL where I want to retrieve all records inside. There are many columns inside the table like NAME, IDENTIFIER, TOTAL. Let's say this table has 6 records, if there is duplicate value under IDENTIFIER column, I want to retrieve the top 1 of those duplicate records + the other non-duplicate records.

For e.g.
**Table in SQL currently:**

----------------------------------------------------------------

NAME | IDENTIFIER | TOTAL

ab | 110011 | 10

cd | 110011 | 20

ef | 110012 | 30

gh | 110013 | 40

ij | 110014 | 50

kl | 110015 | 60

----------------------------------------------------------------
IDENTIFIER of 110011 is repeated but I want to retrieve one of those record.

**The output I want to achieve:**

----------------------------------------------------------------

NAME | IDENTIFIER | TOTAL

ab | 110011 | 10

ef | 110012 | 30

gh | 110013 | 40

ij | 110014 | 50

kl | 110015 | 60

----------------------------------------------------------------

Please help me on this, thanks!

Posted 5-Nov-15 17:57pm

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Suvendu Shekhar Giri · Answer 1 · 2015-11-05T18:49:00

If it is SQL Server, you can use RANK() to do your job.
Try something like-

SQL

SELECT [NAME],IDENTIFIER,TOTAL
FROM
(
	SELECT [NAME],IDENTIFIER,TOTAL,RANK() OVER (PARTITION BY IDENTIFIER ORDER BY TOTAL) AS SlNo
	FROM YourTable
) AS T
WHERE SlNo=1

EXAMPLE:

SQL

SELECT [NAME],IDENTIFIER,TOTAL
FROM
(
	SELECT [NAME],IDENTIFIER,TOTAL,RANK() OVER (PARTITION BY IDENTIFIER ORDER BY TOTAL) AS SlNo
	FROM
	(
		SELECT 'ab' [NAME], 110011 IDENTIFIER, 10 TOTAL
		UNION ALL
		SELECT 'cd', 110011, 20
		UNION ALL
		SELECT 'ef', 110012, 30
		UNION ALL
		SELECT 'gh', 110013, 40
		UNION ALL
		SELECT 'ij', 110014, 50
		UNION ALL
		SELECT 'kl', 110015, 60
	) AS T1
) AS T2
WHERE SlNo=1

Hope, it helps :)

Tejas Sawant 13 · Answer 2 · 2015-11-06T01:45:00

Solution 2

You can check DISTINCT keyword.

Posted 6-Nov-15 1:45am

Tejas Sawant 13

Comments

Maciej Los 6-Nov-15 14:21pm

Have you tried it? In this case, each record is differ from other, because of values in "Name" column.