Why is it getting syntax error.

Question

1.50/5 (2 votes)

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Hello this is my php code:
<!DOCTYPE html>
<html>
<body>

$input = $_POST["value"];
function input($input) {
if ($input === TRUE){
echo "Hello";

}
else {
echo "What are you saying?";

};
};
input($input);

?>
<form method="post" action="">
<input type="text" name="value">
<input type="submit">
</form>

</body>
</html>

It should work like this
1. It should take value from me.
2. Verify it with if/else statement.
3. Print the correct statement.

but this what it is doing
only printing and input box bellow it like this:
what are you saying?

and even after entering value it is still saying same thing.

What I have tried:

i tried to solve it but nothing goes right it happens over and over again

Posted 11-Feb-16 21:35pm

Sahilmohile

Updated 12-Feb-16 1:28am

v2

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2 solutions

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Thomas Daniels · Accepted Answer · 2016-02-11T21:43:00

I can see a few problems with the code:

There's no semicolon after your last echo statement.
When checking whether $input equals "Hello", you use a single equality sign, but that sign is for assigning a value to a variable. Use two or three equality signs (for the difference between these two, see How do the PHP equality (== double equals) and identity (=== triple equals) comparison operators differ? - Stack Overflow[^]).
You have a PHP end tag ?>, but you don't have a start tag. Add <?php before you start with the PHP code.

Jochen Arndt · Accepted Answer · 2016-02-11T21:46:00

Solution 2

Quote:
unexpected end of file

is an indication for a missing closing brace.

In your case there is no closing brace for the input() function:

PHP

$input = $_POST['value'];
function input($input) {
    if ($input = "Hello"){
        echo "Hello";
    
    }
    else {
        echo "What are you saying?"
    
    }
// Insert missing brace here

Posted 11-Feb-16 21:46pm

Jochen Arndt

Comments

Sergey Alexandrovich Kryukov 12-Feb-16 11:02am

5ed.
—SA