Unmanaged code

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Hello,

I'ved came accross the following problem :

I have a variable

IntPtr pointer

to which I know that I have assigned a point structure ( x and y as floats ) .
I need to get the x value.
If I try to write x=pointer->x I get : "The * and -> operators must be applied to a pointer".
How could I get the value of pointer->x ?

Thanks in advance !

Posted 22-Nov-10 8:12am

tamash_ionut

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3 solutions

Solution 2

I believe you may have to use syntax like this. Like John, it has been a very long time since I've done work in C++, so I might just be providing useless info, but on the off chance that I'm right...

*pointer.x

or

((point)*pointer).x

Posted 22-Nov-10 9:30am

fjdiewornncalwe

Solution 1

It's been a while since I did any C++, but try pointer.x

Posted 22-Nov-10 8:29am

#realJSOP

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Peter_in_2780 22-Nov-10 21:36pm

It has indeed been a while! pointer->member is good, as is struct.member :)

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Richard MacCutchan · Accepted Answer · 2010-11-22T10:16:00

You first need to create a pointer to a point structure and cast your pointer object to it, then you can access the structure contents through the point reference. Something like:

IntPtr pointer = ...// your initialization here
Point* pt = (Point*)pointer;
float fx = pt->x;

I may be wide of the mark here but your subject line and tag gives very few clues as to what language you are using (i.e C++, C++/CLI, C#).