How to handle message in between two dialog items using SendMessage() in MFC?

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Hello dear,
Actually i'm having two dialogs in my application along with a Text Field in both.And i want any thing i wrote in 2nd dialog's textbox ,it should display in 1st dialog's text box through a button click in 2nd Dialogbox.
I'm sure,it can possible using either "SendMessage()" OR "PostMessage()" .

But now i'm failing , how to get the handle of 1st Dialog's Textbox which we need to pass in SendMessage() as parameter in 2nd Dialog's sourcecode.

Kindly Please help me soon.Thanks

Posted 16-Sep-11 2:43am

litupkj

Updated 17-Sep-11 9:26am

litupkj

v8

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Albert Holguin · Answer 1 · 2011-09-16T04:45:00

You can simply do it through the CWinApp that runs the show... He has the pointers to everyone, so you can just pass the handle to either dialog as part of the initialization.

Somewhere in CWinApp():

CDialog1 dialog1;
CDialog2 dialog2;

dialog1.mp_other_dialog = &dialog2;
dialog2.mp_other_dialog = &dialog1;

where:
CDialog1 and CDialog2 are derived from CDialog.
and:
CDialog* mp_other_dialog;

Alternatively, you can also make a method in whatever parent class (again, CWinApp could be used) that will return a requested pointer. For example:

CWinApp *theApp;
CDialog* dialog = theApp->GetDialog(TYPE);

epanjohura · Answer 2 · 2011-09-16T04:50:00

Solution 3

You can use "SendMessage()" in the 1st dialog an d "OnReceiveMessage" in the 2nd dialog..

Posted 16-Sep-11 4:50am

epanjohura

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litupkj 16-Sep-11 16:07pm

Thanks Painjoshem.
But Can you please tell me how to get the handle of a TextBox of one Dialog in another Dilog's soucecode.

epanjohura 19-Sep-11 5:04am

can you tell me exactly what you want to put in the 1st / 2nd dialogs?