PHP Coding Problem, Can't Find The Error, PLEASE HELP!!!

Question

1.00/5 (1 vote)

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I have a program set to get variables from a page,
and compare them. If the variable $password does not
match $repassword then it will echo an error. It echo's
the error no matter what, please help

The html page code is:

eeWebHostingArea
Site made by 42cheese Team
Contact us at: hdesk@42cheese.6te.net

HTML

<html>
<head>
<title>Happycraft Survival and Creative</title>


#foreground
{
padding: 5px;
border-radius: 25px; 
-moz-border-radius: 25px; 
-webkit-border-radius: 25px; 
border: 1px solid blue;
background-color: red;
color: green:
}

#navbar
{
background-color: brown;
padding: 5px;
border-radius: 25px; 
-moz-border-radius: 25px; 
-webkit-border-radius: 25px; 
}

.nav
{
background-color: red;
border-radius: 50px; 
-moz-border-radius: 50px; 
-webkit-border-radius: 50px; 
border: 1px solid blue;
text-decoration: none;
color: blue;
padding: 2px;
}

#body
{
background-color: red;
color: blue;
}

#thnx
{
text-align: right;
color: black;
}

#thnx a
{
text-decoration: none;
color: black;
}


</head>
<body>


<marquee style="background-color: red; color: blue; margin-left: 5px; margin-right: 5px;" direction="left" loop="-1" width="99%">
Be Happy!
</marquee>


Home
Apply


Register:
<form method=POST action="registerphp.php">
Username:
<input type="text" name="name">

Password:
<input type="password" name="pass">

Repeat Password:
<input type="password" name="repass">

<input type="submit" value="Submit">
</form>


  
  <script language="JavaScript">
  var data = '&r=' + escape(document.referrer)
	+ '&n=' + escape(navigator.userAgent)
	+ '&p=' + escape(navigator.userAgent)
	+ '&g=' + escape(document.location.href);

  if (navigator.userAgent.substring(0,1)>'3')
    data = data + '&sd=' + screen.colorDepth 
	+ '&sw=' + escape(screen.width+'x'+screen.height);

  document.write('');
  document.write('');
  document.write('');
  </script>

Free site hosting and subdomain byFreeWebHostingArea
Site made by 42cheese Team
Contact us at: hdesk@42cheese.6te.net



</body>
</html>

PHP Code:

PHP

Back");

}

if(!$password == $repassword)
{

die("Password Does Not MatchBack");

}

$query = mysql_query("INSERT INTO happylogin(name,password) VALUES('{$ename}','{$epassword}'");

if($query)
{
echo"Account Created SuccessfullyHome";
$query = mysql_query("SELECT * FROM happylogin WHERE name='$ename'");
$array = mysql_fetch_array($query);
$_SESSION['ID'] = $array['ID'];

$_SESSION['name'] = $name;
}

else
{
die("Error Creating AccountCheck Internet Connection or Contact the 42cheese Team at hdesk@42cheese.6te.net");
}


?>

-AKsicppy

Posted 10-Dec-11 20:06pm

Sicppy

Updated 11-Dec-11 14:55pm

Monjurul Habib

v3

Add a Solution

Comments

thatraja 11-Dec-11 2:41am

what's the error message?

2 solutions

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When answering a question please:

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Uday P.Singh · Accepted Answer · 2011-12-10T21:00:00

Solution 2

you can try this:

PHP

<?php
if($password == $repassword)
{
   $query = mysql_query("INSERT INTO happylogin(name,password) VALUES('   {$ename}','{$epassword}'");

 if($query)
 {
  echo"Account Created SuccessfullyHome";
  $query = mysql_query("SELECT * FROM happylogin WHERE  name='$ename'");
 $array = mysql_fetch_array($query);
 $_SESSION['ID'] = $array['ID'];

  $_SESSION['name'] = $name;
 }

 else
 {
 die("Error Creating AccountCheck Internet Connection or Contact the  42cheese Team at hdesk@42cheese.6te.net");

 }
}
else
{
 die("Password Does Not MatchBack");

}
?>

hope it helps :)

Posted 10-Dec-11 21:00pm

Uday P.Singh

Updated 10-Dec-11 21:01pm

v2

Comments

Monjurul Habib 11-Dec-11 20:51pm

5!

Uday P.Singh 12-Dec-11 4:18am

thank you Monjurul :)

LanFanNinja 11-Dec-11 21:27pm

+5

Uday P.Singh 12-Dec-11 4:18am

thank you LanFanNinja :)

Sicppy 2-Jul-12 4:31am

I haven't got to try your response yet, i have been busy the past few months with some projects I've been working on, but by the looks of the comments it seems to have worked for some other people, I'll give it a shot and get back to you soon,

Thanks

-Jordan

jabba_2000ad · Accepted Answer · 2011-12-10T20:47:00

Solution 1

I'm not a php Dev, but in any other language I use

PHP

if(!$password == $repassword) is the same as if( (!$password) == $repassword) 

i.e. !password evaluates first and then is compared with $repassword

try using

if( ! ($password == $repassword ))

Regards

Richard

Posted 10-Dec-11 20:47pm

jabba_2000ad

Updated 11-Dec-11 14:51pm

v2

Comments

Sicppy 11-Dec-11 2:57am

I am afraid to say it didn't work, thanks for your response though,
-AKsicppy

Monjurul Habib 11-Dec-11 20:51pm

5!

LanFanNinja 11-Dec-11 21:17pm

+4 Correct or better yet
if ($password != $repassword)
or
if ($password !== $repassword)

However you are correct this code

if (!$password == $repassword)

Is straight up WRONG! Using this code the passwords will always match unless one of the strings are empty ("").

for example
$pass = "I am BIG bird";
$rePass = "dog";

if (!$pass == $rePass)
{
echo $pass." and ".$rePass." do not match!";
}
else
{
echo "Match";
}

this code will always echo Match.