load partial view dynamically using jquery

Question

0.00/5 (No votes)

See more:

Hi All,

I want to load the partial views according to the condition here with the following code it's not working

my jquery fn

XML

var ww = document.body.clientWidth;

$(document).ready(function () {

    if (ww < 768) {


        $('<div>').appendTo('#div_partial').load('Html.RenderPartial("nav_partial", "Mydemo");');
    }
    else {

        $('<div>').appendTo('#div_partial').load('Html.RenderPartial("nav_partial_large", "Mydemo");');
    }
})

Here is my controller

SQL

[ChildActionOnly]
       public PartialViewResult nav_partial()
       {

           return PartialView();
       }
    

       [ChildActionOnly]
       public PartialViewResult nav_partial_large()
       {

           return PartialView();
       }

Pls help me

Thanks,
Soumya

Posted 12-Dec-12 3:14am

soumyaraj

Add a Solution

2 solutions

Solution 1

Html.RenderPartial is server side code. You would need a @ in front of it, and you in general need to have your js contain the final HTML, not a server side call. An AJAX call to get the HTML makes the most sense IMO.

Posted 12-Dec-12 10:10am

Christian Graus

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

soumyaraj · Accepted Answer · 2012-12-13T01:40:00

In js file

if (condition) {
$.ajax({
cache: false,
type: 'GET',
url: '/demo/partialview1',
data: null,
success: OnSuccessCall,
error: OnErrorCall
});

}
else {
$.ajax({
cache: false,
type: 'GET',
url: '/demo/partialview2',
data: null,
success: OnSuccessCall,
error: OnErrorCall
});

}

})

var OnSuccessCall = function (response) {

$('#divname').html(response.valueOf(0))
}
var OnErrorCall = function () {

alert(request.status + " " + request.statusText);

}

In controller

SQL

public ActionResult partialview1()
        {


          return PartialView();
         }
      public ActionResult partialview2()
      {


          return PartialView();
      }