Create MS word table, using C#.

Question

0.00/5 (No votes)

See more:

Hi,

I have a word documant that contains text box shapes.
I'm tring to create a MS Word table inside one of this text box shapes.
But I'm having problem with the range setings.
(Microsoft.Office.Interop.Word.Range wordRange = wordDoc.Shapes[wordShapeIndexes[id]].TextFrame.ContainingRange;
throws exeption - The index into the specified collection is out of bounds.), can some one help me please ?

Here is my function:

C#

public void setWordShapeDataTask(int id, DataGridView data)
      {
          int tableRowNumber = data.RowCount + 1;
          Microsoft.Office.Interop.Word.Table wordTable;
          Microsoft.Office.Interop.Word.Range wordRange =  wordDoc.Shapes[wordShapeIndexes[id]].TextFrame.ContainingRange;

          wordTable = wordDoc.Tables.Add(wordRange, tableRowNumber, 5);

          wordTable.Cell(0, 0).Range.Text = "Num";
          wordTable.Cell(0, 1).Range.Text = "Task";
          wordTable.Cell(0, 2).Range.Text = "Recipiens";
          wordTable.Cell(0, 3).Range.Text = "Time";
          wordTable.Cell(0, 4).Range.Text = "Status";

          for (int i = 1, j = 0; i < tableRowNumber; i++, j++)
          {
              wordTable.Cell(i, 0).Range.Text = i.ToString();
              wordTable.Cell(i, 1).Range.Text = data.Rows[j].Cells["TaskBody"].Value.ToString();
              wordTable.Cell(i, 2).Range.Text = data.Rows[j].Cells["Recipiens"].Value.ToString();
              wordTable.Cell(i, 3).Range.Text = data.Rows[j].Cells["DueDate"].Value.ToString();
              wordTable.Cell(i, 4).Range.Text = data.Rows[j].Cells["Status"].Value.ToString();
          }
      }

Posted 5-Jan-13 21:53pm

supernatik

Updated 14-Dec-17 2:39am

v4

Add a Solution

2 solutions

Solution 1

Looks like you are looping from index 1 to tableRowNumber for data rows. It should start from 0 till rowCount.
Try:

C#

// with int tableRowNumber = data.RowCount + 1;
for (int i = 0; i < tableRowNumber-1; i++)

Posted 5-Jan-13 22:16pm

Sandeep Mewara

v2

Comments

Sandeep Mewara 6-Jan-13 4:35am

Even then, following will throw index error:
data.Rows[i].Cells when i=tableRowNumber highest value.
As tableRowNumber = rowCount+1 ... thus, you try to access a row at index that does not exists.

Start from 1 for i but go till 1 less of tableRowNumber. Ex:
for (int i = 1; i < tableRowNumber-1; i++)

supernatik 6-Jan-13 4:38am

Thank you for your answer, I fixed the i = 0 issue, added j.
But My original problem is creating the table inside the text box shape.
I having an exeption with the range.

Microsoft.Office.Interop.Word.Range wordRange = wordDoc.Shapes[wordShapeIndexes[id]].TextFrame.ContainingRange;

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

supernatik · Accepted Answer · 2013-01-06T20:40:00

C#

public void setWordShapeDataTask(int id, DataGridView data)
        {
            try
            {
                int tableRowNumber = data.RowCount + 1;
                Microsoft.Office.Interop.Word.Table wordTable;
                foreach (Microsoft.Office.Interop.Word.Shape shape in wordDoc.Shapes)
                    if (shape.ID == wordShapeIndexes[id])
                    {
                        Microsoft.Office.Interop.Word.Range wordRange = shape.TextFrame.ContainingRange;

                        wordTable = wordDoc.Tables.Add(wordRange, tableRowNumber, 5);
                        //wordTable = wordDoc.Tables.Add(wordRange, 4, 5);
                        wordTable.Range.Font.Size = 8;
                        wordTable.set_Style("Table Grid 8");

                        wordTable.Cell(1, 1).Range.Text = "Num";
                        wordTable.Cell(1, 2).Range.Text = "Task";
                        wordTable.Cell(1, 3).Range.Text = "Recipiens";
                        wordTable.Cell(1, 4).Range.Text = "Time";
                        wordTable.Cell(1, 5).Range.Text = "Status";

                        for (int i = 2, j = 0; i <= tableRowNumber; i++, j++)
                        {
                            wordTable.Cell(i, 1).Range.Text = (i-1).ToString();
                            wordTable.Cell(i, 2).Range.Text = data.Rows[j].Cells["TaskBody"].Value.ToString();
                            wordTable.Cell(i, 3).Range.Text = data.Rows[j].Cells["Recipiens"].Value.ToString();
                            wordTable.Cell(i, 4).Range.Text = data.Rows[j].Cells["DueDate"].Value.ToString();
                            wordTable.Cell(i, 5).Range.Text = data.Rows[j].Cells["Status"].Value.ToString();
                        }
                    }
            }
            catch (Exception)
            {
            }

        }