error is like object reference not set

Question

1.00/5 (1 vote)

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i want to add seat numbers selected by a single user into the database.

C#

void BindSeats()
   {
       Label14.Text = chargePerSheet.ToString();
       string sel = String.Join(",", (from b in objEntities.BookingDetails
                                      join s in objEntities.SeatDetails on b.BookingID equals s.BookingID
                                      where b.TourID == tourID
                                      select s.SeatID).ToArray());
       ClientScript.RegisterStartupScript(this.GetType(), "Init", "init([" + sel + "]);", true);

   }

getting an error like 'object reference not set' the code is like:

C#

protected void btnSubmit_Click(object sender, EventArgs e)
   {
       paymentmethod();
       sendMail();

       StarBusModel.BookingDetail objBooking = new StarBusModel.BookingDetail();
       objBooking.TourID = tourID;
       objBooking.Name = Label11.Text;
       objBooking.Phone = TextBox2.Text;
       objBooking.Amount = Convert.ToDecimal(Request.Form[Label14.ClientID]);
       string[] seats = Request.Form[Label13.ClientID].Split(new char[] { ',' });
       for (int i = 0; i < seats.Length; i++)
           objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });
       objEntities.BookingDetails.AddObject(objBooking);
       objEntities.SaveChanges();
       BindSeats();




       Response.Redirect("thankyou.aspx");

Posted 1-May-13 6:24am

degrader404

Updated 1-May-13 20:55pm

v3

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Comments

Richard C Bishop 1-May-13 12:25pm

You need to debug and see where the exception is being thrown. Once you have done that, it will be clear that you are using an object that you did not instantiate.

degrader404 1-May-13 12:34pm

actually i want to add two distinct numbers in my database that holds values for tickets selected

Richard C Bishop 1-May-13 12:35pm

See my solution, it is what you need.

degrader404 1-May-13 12:45pm

still getting the same error:Object reference not set to an instance of an object.

Richard C Bishop 1-May-13 12:47pm

Debug again and see where it is coming from now. My guess it is coming from "objEntities". You never instantiate that object either.

degrader404 1-May-13 13:07pm

it shows the same.can you give me your email-id so that i can send you all of my code.then you can go through it. plzzz

Richard C Bishop 1-May-13 13:58pm

Just use the "Improve question" widget and add what you have now below what is already in the thread. Show them both.

degrader404 2-May-13 2:47am

now i am getting a new error:
Input string was not in a correct format.
Line 136: objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });

HariPrasad katakam 1-May-13 12:26pm

In which line you are getting the error? and also share the full error message

degrader404 1-May-13 12:41pm

at this line
string[] seats = Request.Form[Label13.ClientID].Split(new char[] { ',' });

degrader404 1-May-13 12:46pm

this is the error
Object reference not set to an instance of an object.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.NullReferenceException: Object reference not set to an instance of an object.

HariPrasad katakam 1-May-13 12:51pm

Are you sure that you have a Label with ID Label13 in your webpage? and is it stand alone page or having master page?

degrader404 1-May-13 12:53pm

Yes i have it.It has a master page.

degrader404 1-May-13 13:00pm

It has a label with that id and a master page.

HariPrasad katakam 1-May-13 13:13pm

replace the Line
string[] seats = Request.Form[Label13.ClientID].Split(new char[] { ',' });

With

string[] seats = Label13.Text.Split(new char[] { ',' });

degrader404 2-May-13 2:32am

i did what you said.but now it is showing anew error on this line:
objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });

HariPrasad katakam 2-May-13 3:25am

What is the value you have in Label? i mean Label13.Text value? As per your logic it should be comma separated numeric.. Ex: 100,101,102 is That correct? if it is not the error message could be "Format exception was unhandled, Input string was not in a correct format.".

degrader404 2-May-13 12:02pm

yes your correct.the error message is 'Input string was not in a correct format.'

HariPrasad katakam 2-May-13 3:43am

And also try to replace the line

objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });

with

objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID =int.TryParse(seats[i]) });

degrader404 2-May-13 12:35pm

i replaced it but now it shows:
Error 1 No overload for method 'TryParse' takes 1 arguments D:\WebSite4\payment.aspx.cs 140 77 D:\WebSite4\

HariPrasad katakam 3-May-13 6:12am

Sorry Was in hurry, below is one alternative i can suggest. might not be a effective way of coding,but until you find some other solution you can use this

replace below lines of code

string[] seats = Request.Form[Label13.ClientID].Split(new char[] { ',' });
for (int i = 0; i < seats.Length; i++)
objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });

with

string[] seats = Request.Form[Label13.ClientID].Split(new char[] { ',' });
int temp;
for (int i = 0; i < seats.Length; i++)
if(int.TryParse(seats[i],out temp))
objBooking.SeatDetails.Add(new StarBusModel.SeatDetail() { SeatID = Convert.ToInt32(seats[i]) });

But I am suspecting your label(which is storing all the selected seats with comma separated) may contain other than int values. please check that front as well.

degrader404 3-May-13 12:57pm

thanks for your time.but now its showing an error:
The specified cast from a materialized 'System.String' type to the 'System.Int32' type is not valid.
at
string sel = String.Join(",", (from b in objEntities.BookingDetails
join s in objEntities.SeatDetails on b.BookingID equals s.BookingID
where b.TourID == tourID
select s.SeatID).ToArray());

degrader404 3-May-13 13:05pm

can i mail you all of my code

HariPrasad katakam 3-May-13 13:19pm

Ok do that.send it to urstrulyhariprasad@gmail.com. but it may take some time to give you reply.

degrader404 4-May-13 11:23am

i have send the email.plz check it.thanks man.

degrader404 8-May-13 2:01am

hey did you get the solution ?

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Richard C Bishop · Answer 1 · 2013-05-01T06:29:00

Solution 1

It is stemming from "string[] seats = """. You never instantiated a string array. It should look like this:

C#

string[] seats = new string[1];

Then you can assign it the value you have.

Posted 1-May-13 6:29am

Richard C Bishop

Updated 1-May-13 6:45am

v4