Getting current date by N No of DaysDifference

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Hey friends i am facing a problem please help me.

I have Start date and End Date as well as i have NoofDaysDifference which could be 1,2,3,5,7,10,12,15,18,20,25,30.

I have to get current date on the basis No of (1 or 2 or 3 or 5 or 7 or 10 like wise) NoofDaysDifference in month/total duration.

Current Date should be decrement by NoofDaysDifference.

I have done for every one days like this

C#

int NoofDays;

NoofDays = dtEnd.Subtract(dtstart).Days;

while (dtEnd.Date > dtstart.Date && NoofDays >= 0)
{
   DateTime CurrentDate = dtstart.AddDays(NoofDays);
   NoofDays--;
}

Posted 5-Sep-13 20:04pm

viky.singh

Updated 5-Sep-13 20:29pm

phil.o

v2

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Sergey Alexandrovich Kryukov 6-Sep-13 3:02am

And what's the problem?
—SA

OriginalGriff 6-Sep-13 3:51am

That doesn't make much sense, even with your added comment.
Remember, we can't see your screen, or access your HDD, or read your mind, so we only get to work with exactly what you tell us.
Perhaps if you gave us an example or two? With a start date, end date, NoofDays value and what you expect to get at the end so we can work out what you are trying to achieve? And explain what is wrong with your current code?
Use the "Improve question" widget to edit your question and provide better information.

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Mike Meinz · Answer 1 · 2013-09-05T23:54:00

Your question is not clear. Here are two examples of date computations. Do either of these come close to your requirements? If not, please use Improve Question and show a few examples using real dates that will demonstrate what you are trying to do.

Example 1

C#

StringBuilder strOutput = new StringBuilder(4096);
DateTime dtStart = DateTime.Parse("2013-09-01");
DateTime dtEnd = DateTime.Parse("2013-09-05");
int NoOfDays=3;
DateTime dt;
dt = dtStart.Date;
while (dt <= dtEnd)
{
    strOutput.AppendLine(dt.ToString("yyyy-MM-dd"));
    dt=dt.AddDays(NoOfDays);
}
Console.WriteLine(strOutput);

Output
2013-09-01
2013-09-04

Example 2

C#

DateTime dtStart = DateTime.Parse("2013-09-01");
DateTime dtEnd = DateTime.Parse("2013-09-05");
int NoOfDays;
DateTime dt;
NoOfDays = dtEnd.Subtract(dtStart).Days;
dt = DateTime.Now.Date.AddDays(-(double)NoOfDays);
Console.WriteLine("Start: " + dtStart.ToString("yyyy-MM-dd") + ", End: " + dtEnd.ToString("yyyy-MM-dd"));
Console.WriteLine("Days Difference: " + NoOfDays );
Console.WriteLine("Now=" + DateTime.Now.Date.ToString("yyyy-MM-dd") + ", Computed Date=" + dt.Date.ToString("yyyy-MM-dd"));

Output
Start: 2013-09-01, End: 2013-09-05
Days Difference: 4
Now=2013-09-06, Computed Date=2013-09-02

Note: A time value is included in the value stored in the DateTime Class. You can use string formatting when displaying a DateTime Class value to not display the time portion.

viky.singh · Answer 2 · 2013-09-06T00:15:00

if (ddlScheduledMedicines.SelectedIndex == 1)
{
daysdifference = 3;
}
else if (ddlScheduledMedicines.SelectedIndex == 2)
{
daysdifference = 5;
}
else if (ddlScheduledMedicines.SelectedIndex == 3)
{
daysdifference = 7;
}

DateTime CurrentDate =dtstart.Date;

while (CurrentDate<dtEnd)
{
CurrentDate = CurrentDate.AddDays(daysdifference);
}

Getting current date by N No of DaysDifference

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