How to display the no. of items from MYSQL based on the value selected from Dropdown

Question

0.00/5 (No votes)

See more:

//This is my jobsearch.html

//I am selecting values from all the dropdowns and populating them to search.php where I will be getting job_title from database.

//What i need is, i should display the number of jobs with respect to "job_count"(Drop Down) 


&lt;html&gt;
&lt;head&gt;
&lt;style&gt;

#job_listings
{

background-color:#00FFFF;
width:500px;
height:100px;
overflow:scroll;

}

&lt;/style&gt;
&lt;h4&gt;Job Search&lt;/h4&gt;	
	&lt;script type="text/javascript"&gt;&lt;/script&gt;
	&lt;script src="../js/jquery-1.9.1.js"&gt;&lt;/script&gt;
	&lt;script src="../js/jquery.tmpl.min.js"&gt;&lt;/script&gt;
&lt;script&gt;
		jQuery(document).ready(function() 
		{
			jQuery.ajax(
			{
				type: 'GET',
				url: 'sample.php',
				dataType: 'JSON',
				success:function(data)
				{
					for(i=0;i&lt;jQuery(data).length;i++)
					{
						jQuery('#jobcategory').append('&lt;option value = '+ data[i].jobcategory+'&gt;' + data[i].jobcategory + '&lt;/option&gt;');
					}
				}
			});
		});
&lt;/script&gt;

&lt;script&gt;
		jQuery(document).ready(function() 
		{
			jQuery.ajax(
			{
				type: 'GET',
				url: 'sample.php',
				dataType: 'JSON',
				success:function(data)
				{
					for(i=0;i&lt;jQuery(data).length;i++)
					{
						jQuery('#jobtype').append('&lt;option value = '+ data[i].jobtype+'&gt;' + data[i].jobtype + '&lt;/option&gt;');
					}
				}
			});
		});
&lt;/script&gt;

&lt;script&gt;
		jQuery(document).ready(function() 
		{
			jQuery.ajax(
			{
				type: 'GET',
				url: 'sample.php',
				dataType: 'JSON',
				success:function(data)
				{
					for(i=0;i&lt;jQuery(data).length;i++)
					{
						jQuery('#company').append('&lt;option value = '+ data[i].company+'&gt;' + data[i].company + '&lt;/option&gt;');
					}
				}
			});
		});
&lt;/script&gt;

 
&lt;script&gt;
jQuery(document).ready(function() 
		{
			jQuery('#submit').click(function()
			{

				var jobDetails =[];

				var obj={};


				obj.jobcategory=jQuery('#jobcategory').val();

				obj.jobtype=jQuery('#jobtype').val();

				obj.company=jQuery('#company').val();

				obj.startdate=jQuery('#startdate').val();

				obj.enddate=jQuery('#enddate').val();

				obj.jobcount=jQuery('#jobcount').val();

				jobDetails.push(obj);

			var jsonString =JSON.stringify(jobDetails);


		
				jQuery.ajax(
				{
					type: 'GET',
					url: 'search.php',
					data: { 'jobDetailsData': jsonString },
					success:function(data)
					{

						{
						jQuery('#job_listings').append(data);
						}
						
					}
					
				});
			});
		});

	&lt;/script&gt;

&lt;/head&gt;
&lt;body&gt;
	&lt;form id="search" name="jobSearch"&gt;
		&lt;div&gt;
			Job Categories:&lt;select id="jobcategory" value="jobcategory"&gt;
			&lt;option&gt;Select Job Category&lt;/option&gt;
			&lt;/select&gt;&lt;br&gt;&lt;br&gt;


			Job Type:&lt;select id="jobtype" value="jobtype"&gt;
			&lt;option&gt;Select Job Type&lt;/option&gt;
			&lt;/select&gt;&lt;br&gt;&lt;br&gt;

			Company:&lt;select id="company" value="company"&gt;
			&lt;option&gt;Select Company&lt;/option&gt;
			&lt;/select&gt;&lt;br&gt;&lt;br&gt;

			Start Date:&lt;input type="date" id="startdate" value="startdate"&gt;&lt;br&gt;&lt;br&gt;

			End Date:&lt;input type="date" id="enddate" value="enddate"&gt;&lt;br&gt;&lt;br&gt;

			No. Of Jobs:&lt;select id="jobcount" value="jobcount"&gt;
			&lt;option&gt;Select&lt;/option&gt;
			&lt;option&gt;5&lt;/option&gt;
			&lt;option&gt;10&lt;/option&gt;
			&lt;option&gt;15&lt;/option&gt;
			&lt;option&gt;20&lt;/option&gt;
			&lt;/select&gt;&lt;br&gt;&lt;br&gt;

			&lt;input type="button" id="submit" value="Submit"/&gt;

			&lt;/div&gt;

&lt;div id="job_listings" style="" class=jobs_list&gt;

&lt;/div&gt;
&lt;/form&gt;
&lt;/body&gt;
&lt;/html&gt;




//This is my search.php

&lt;?php
mysql_connect("localhost","root","");

mysql_select_db("plugins");

$jobDetailsData = json_decode($_GET['jobDetailsData']);

foreach($jobDetailsData as $jobDetailsData)
{
$jobcategory = mysql_real_escape_string($jobDetailsData-&gt;jobcategory);
$jobtype = mysql_real_escape_string($jobDetailsData-&gt;jobtype);
$company = mysql_real_escape_string($jobDetailsData-&gt;company);
$startdate = mysql_real_escape_string($jobDetailsData-&gt;startdate);
$enddate = mysql_real_escape_string($jobDetailsData-&gt;enddate);
$jobcount = mysql_real_escape_string($jobDetailsData-&gt;jobcount);


$result=mysql_query("select job_title from job_listings where (job_category='$jobcategory' OR job_type='$jobtype' OR company_name='$company') AND (start_date='$startdate' AND end_date='$enddate')");



}
//echo $result;
$data=array();
if($result)
{


	while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) 

		{ 

		$row_array['job_title'] = $row['job_title'];

		array_push($data,$row_array);

		}


}
echo json_encode($data);



mysql_close();

?&gt;


//please help me on this

Posted 19-Mar-14 5:49am

Janardhanam Julapalli

Updated 23-Mar-14 17:52pm

v3

Add a Solution

Comments

Janardhanam Julapalli 20-Mar-14 5:06am

Anyone help me out on this

CHill60 23-Mar-14 13:15pm

Do yourself a favour ... use the Improve question link next to your question. Highlight all of the code segment and hit Ctrl-C. Now hit Del. Now use Ctrl-V ... a pop-up menu will appear to the right, select the "Code Block" radio button and hit ok, then submit your question again. It will go back into the queue, and should be easier for people to read. While you are doing that you might want to remove any code that isn't relevant to your question

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

ShubhamSaxena · Accepted Answer · 2014-04-02T10:41:00

your code is hard to understand... use proper styling

but what i understood is you want to limit the no of results frm a sql query to a no from dropdown list... here it is.. improve your query to

select job_title from job_listings where (job_category='$jobcategory' OR job_type='$jobtype' OR company_name='$company') AND (start_date='$startdate' AND end_date='$enddate') limit yourNumber(dropdown list value)