How do I show a messagebox from Excel's XLL function ?

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I have the following piece of code inside a function and I need to shows a user's error message. But the message is not shown. Only the return's value... What did I do wrong ?

Regards.

C++

const double dia = 1.0;

 xloper xStr, xInt;

 xStr.xltype = xltypeStr;
 xStr.val.str = new_xlstring("User's message.");
 xInt.xltype = xltypeInt;
 xInt.val.w = 2; 


if(terNum < segNum)
{
    Excel4(xlcAlert, NULL, 2, &xStr, &xInt);
    return 0.0;
}

free(xStr.val.str);

Posted 22-Apr-14 5:01am

Member 9699301

Updated 21-Oct-14 13:32pm

Nelek

v2

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Sir David · Answer 1 · 2014-10-21T08:17:00

I have never managed to get xlcAlert to work in functions. So, I use MessageBoxW. Here is an example, using your code as a starting point, which works:

C++

__declspec(dllexport) LPXLOPER12 XLLShowMessageA (void)
{
    static XLOPER12 xReturn;
    int             terNum, segNum, rc;


    terNum = 1;
    segNum = 2;
	
    xReturn.xltype = xltypeNum;
    xReturn.val.num = 0;  

    if (terNum < segNum)
    {
        MessageBoxW (NULL, L"User message.", L"Dialog title.", 
                     MB_OK | MB_SETFOREGROUND );		
        return &xReturn;
    }
  
    return &xReturn;
}

David Wilkinson (UK)