How to change Dateformate in XSLT

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Hi,

I need to change the date format (dateFrom) in the following (Tag) xml.

*change by: dd/mm /yyyy

XML

<CancellationPolicies>
          <CancellationPolicy amount="355.500" dateFrom="20140613" time="2359" /></CancellationPolicies>

For that I use this xslt:

XML

What to add in the xslt?

<pre><?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:ms="urn:schemas-microsoft-com:xslt"
    xmlns:dt="urn:schemas-microsoft-com:datatypes"
    version="1.0">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:template match="/">
        <xsl:apply-templates select="@*|node()"/>
    </xsl:template>
    <xsl:template match="ServiceHotel/AvailableRoom/HotelRoom/RoomType">
        Política de cancelación: Tipo Hab. <xsl:value-of select="@characteristic"/>  codigo:<xsl:value-of select="@code"/> 
    </xsl:template>
    
    <xsl:template match="//CancellationPolicies/CancellationPolicy">
       
       Si cancelas después de las <xsl:value-of select="@time"/> PM del  <xsl:value-of select="@dateFrom"/> se aplicaran unos gastos de:<xsl:value-of select="@amount"/>   <xsl:value-of select="//*/Currency/@code"/>
    </xsl:template>

  </xsl:stylesheet>

Thanks.

Posted 13-May-14 5:47am

Nestor Pallero

Updated 13-May-14 5:50am

v3

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Nestor Pallero · Accepted Answer · 2014-05-13T10:43:00

Solution 1

XML

<xsl:template match="CancellationPolicy">
      <xsl:value-of select="concat(substring(@dateFrom, 7, 2), '/', substring(@dateFrom, 5, 2), '/', substring(@dateFrom, 1, 4))"/>
</xsl:template>

Posted 13-May-14 10:43am

Nestor Pallero