C Language Question.

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Hello, I was just writing a simple basic program in C language in Microsoft Visual Studio 2010. There is a problem occurred in it as follows in a program.

XML

//Program showing all the binary operators used in C.

#include "stdafx.h"
#include<stdio.h>
#include<conio.h>

void main()
{
    int x,y,c,d;

    printf("Enter The Value of X and Y :    ");
    scanf("%d %d",&x,&y);
    printf("\n\nThe integers are        %d & %d\n",x,y);
    printf("\nThe Addition gives:-      %d\n",x+y);
    printf("\nThe Subtraction gives:-       %d\n",x-y);
    printf("\nThe Multiplication gives:-    %d\n",x*y);
    printf("\nThe Division gives:-      %d\n",x/y);
    printf("\nThe Modulus gives:-       %d\n",x%y);
    printf("\nThe Increment gives:-     %d  &  %d\n",x++,y++);
    printf("\nThe Decrement gives:-     %d  &  %d\n",x--,y--);

    getch();
}

Then I got the Output.

Enter The Value of X and Y : 6 5

The integers are 6 & 5
The Addition gives:- 11
The Subtraction gives:- 1
The Multiplication gives:- 30
The Division gives:- 1
The Modulus gives:- 1
The Increment gives:- 6 & 5
The Decrement gives:- 7 & 6

The problem is in Increment and Decrement operation. Is that a software fault or I missed something! But I think tried everything in Visual Studio 2010 but output wont change.
Thanx.

Posted 21-Jul-14 5:08am

VISH_a_CODE

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Sergey Alexandrovich Kryukov · Accepted Answer · 2014-07-21T05:22:00

Solution 1

There is no a problem at all. It all is calculated as expected. Make sure you understand what a pre-increment should do, know the difference between pre-increment and post-increment.

—SA

Posted 21-Jul-14 5:22am

Sergey Alexandrovich Kryukov

Comments

VISH_a_CODE 21-Jul-14 13:05pm

Thnx for your clarification sir, and I am using post increment and decrement operation. But still why doesn't it shows right output. Which would be 7 and 8 for increment and 5 and 4 for decrement.

Sergey Alexandrovich Kryukov 21-Jul-14 13:25pm

It is a right output. If you need different output (you never defined what it should be), use preincrement, or do it in separate steps as Solution 2 shows.
I recommend you sort things in your head and then accept both Solution 1 and 2 (green "Accept" button).
—SA

VISH_a_CODE 21-Jul-14 21:38pm

Thnx...:)

Sergey Alexandrovich Kryukov 21-Jul-14 23:11pm

You are welcome.
—SA

OriginalGriff · Accepted Answer · 2014-07-21T05:23:00

No, that's right.

C#

x++

is a postincrement operation - it gets the value then increases the source by one and uses teh value it started with.
So

C++

printf("\nThe Increment gives:-     %d  &  %d\n",x++,y++);

Is the equivalent of:

C++

printf("\nThe Increment gives:-     %d  &  %d\n",x,y);
x = x + 1;
y = y + 1;

There is a preincrement operator if you want to try that instead:

C++

printf("\nThe Increment gives:-     %d  &  %d\n",++x,++y);

That is the equivalent of:

C++

x = x + 1;
y = y + 1;
printf("\nThe Increment gives:-     %d  &  %d\n",x,y);

Which might be what yopu were expecting.