understand xml and urls in Java

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Java

I am trying to use this code to recreate similar application in .Net environment, but I am little unclear of the logic. Hence I would like to seek some assistance, in explaining, what is going on in the code below:

There is a contentCreator class, which creates a issue & I am little unsure, what its doing here return api.create(publication.findLink("issue"), Utils.renderXml(document));:

//ContentCreator

	public static ApiObject createIssue(NotessaApi api, ApiObject publication, Issue issue) throws IOException {
		Document document = Utils.createEmptyDocument();
		Node node = Utils.createNode(document, "issue");
		
		Utils.addXml(document, node, "title", issue.getTitle());
		Utils.addXml(document, node, "approval_status", issue.getApprovalStatus());
		Utils.addXml(document, node, "display_title", issue.getDisplayTitle());
		Utils.addXml(document, node, "display_date", issue.getDisplayDate());
		List<Property> properties = issue.getProperties();
		if(!properties.isEmpty()) {
			Node container = Utils.createNode(document, node, "properties");
			for(Property property : properties) {
				Element element = Utils.createNode(document, container, "property");
				element.setAttribute("name", property.getName());
				Utils.addXml(document, element, "value", property.getValue());
			}
		}
		
		return api.create(publication.findLink("issue"), Utils.renderXml(document));
	}

Is it creating the issue xml and forwarding it to the findlink url from the API Object class.

API Object class creates the following two methods:

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;

import javax.xml.namespace.QName;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;
	
public URL findLink(String rel) {
		String result = xpath("//link[contains(@rel,'" + rel + "')]/@href");
		try {
			return new URL(result);
		} catch(MalformedURLException e) {
			throw new RuntimeException(e);
		} 
	}

	public URL getSelfLink() throws MalformedURLException {
		String uri = xpath("//@uri");
		return new URL(uri); 
	}

Any further advice, would be most appreciated. Many thanks.