How to Read a file using open file Dialog Box

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Hi
I have a browse button and text box and when i click on that browse button file dialog box is opening and now my concern is the selected path for that file should be opened in tree view box.. can you please help me in that..

Posted 10-Nov-14 23:09pm

Karthik Bilakanti

Updated 10-Nov-14 23:14pm

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Richard MacCutchan 11-Nov-14 5:22am

Please explain what you mean by "the selected path for that file should be opened in tree view box".

Karthik Bilakanti 11-Nov-14 5:26am

I want to open an excel sheet in tree view control using open file dilog box thats my issue.

Richard MacCutchan 11-Nov-14 5:35am

Fine, but as a technical explanation of your problem that makes no sense.

The OpenFile dialog is used to obtain a file path from the user. You can then read that file in various different ways depending on its content. Similarly you can add data to a TreeView in different ways. You need to read the documentation for all these classes to see how they fit with your requirements.

Karthik Bilakanti 11-Nov-14 5:45am

Thank you

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OriginalGriff · Answer 1 · 2014-11-10T23:25:00

Get the file name from the OpenFileDialog.FileName property, and use string.Split to break it into it's component folders with the backslash character.

Then loop through each string in the array Split returns, creating a new node for each and add it into the Nodes property of the previous one.

C#

OpenFileDialog ofd = new OpenFileDialog();
if (ofd.ShowDialog() == DialogResult.OK)
    {
    string[] parts = ofd.FileName.Split('\\');
    TreeNodeCollection previousNodes = myTreeView.Nodes;
    foreach (string part in parts)
        {
        TreeNode node = new TreeNode(part);
        previousNodes.Add(node);
        previousNodes = node.Nodes;
        }
    myTreeView.ExpandAll();
    }