How this code is Running?

Question

1.00/5 (2 votes)

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Java

interface i1 extends Object
{
	void show();
}
class Sigma implements i1
{
	public void show()
	{
		System.out.println("Hanosh");
	}
	public String toString()
	{
		return "Manish";
	}
	public static void main(String arg[])
	{
		i1 i=new Sigma();
		i.show();
		String s=i.toString();
	}
}

Posted 18-Nov-14 2:18am

Member 11243651

Updated 18-Nov-14 5:14am

Manas Bhardwaj

v2

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Richard MacCutchan 18-Nov-14 8:25am

Probably magic.

[no name] 18-Nov-14 17:09pm

Google for "java hello world" and have a look to from the very basic to the basic examples.

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Manas Bhardwaj · Answer 1 · 2014-11-18T05:24:00

I am not sure the intention of this question, but I am quite sure that you need to start reading about programming and this particular language in question.

However, let me list down the areas which program cover:
Any program starts via an Entry Point which is called as Main Function.

http://en.wikipedia.org/wiki/Entry_point[^]

The first statement in the function instantiates a new object of Sigma class.

http://en.wikipedia.org/wiki/Class_(computer_programming)[^]

What you would also notice that this class implements a particular interface.

http://en.wikipedia.org/wiki/Interface_(computing)[^]

Some other concepts which would see here are static members and the access levels of members (Public, Private etc.)

http://en.wikipedia.org/wiki/Method_(computer_programming)#Static_methods[^]

http://msdn.microsoft.com/en-us/library/ms173121.aspx[^]

OriginalGriff · Answer 2 · 2014-11-18T02:32:00

Solution 1

It's not magic - but it's not simple to explain either. Start reading here: The Jave Tutorials: Inheritance[^] when you have finished, you should have a better idea.

Posted 18-Nov-14 2:32am

OriginalGriff