In VS 2013 for Web, need to send a URL on button click to a web service.

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I have a webservice on a remote server that changes the state of a hardware I/O port to 'ON' when this URL is sent to the remote server using a web browser: http://agratek.dyndns.org:8080/webservice?Op=Actuate&NodeID=2&PortID=0&Value=ON. I need to add a button to an ASP.NET web page that does the same thing.

My code in the Visual Studio for Web 2013 .aspx webform file creates the button:

<asp:Button ID="butValveON" runat="server" OnClick="butValveON_Click" Text="Valve ON" />

And this in the code-behind .cs file handles the button click event:

C#

protected void butValveON_Click(object sender, EventArgs e)
{
    //Send the URL to remote server, wait for and capture response
}

I would like to wait for and capture the webservice's "OK" response to the command. Can someone suggest an approach or better, a code fragment to do this please? The webservice is running now if you would like to try it..it will return [ "OK" ]

Posted 4-Dec-14 12:27pm

Gordon Minns

Updated 4-Dec-14 12:32pm

v2

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ZurdoDev 4-Dec-14 21:20pm

1. I highly recommend removing the actual link. Not a good idea to publish that on the internet.
2. What is the webservice expecting? XML? Http post? You need to know what it expects.

Gordon Minns 5-Dec-14 0:28am

Hi Ryan... Thanks for responding...

The webservice server is only a test server and no harm will be done if people try to access it. But you are right... who knows what evils lurk out there...

You wrote: What is the webservice expecting? XML? Http post? You need to know what it expects.

The webservice is written to operate on the arguments sent in the URL I mentioned. We use JSON to send data to the requesting web page, but the URL as written effects the changes in the I/O ports.

ZurdoDev 5-Dec-14 7:29am

Then Solution 1 from DamithSL will likely work.

2 solutions

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DamithSL · Answer 1 · 2014-12-04T16:16:00

Solution 1

sample using WebClient

C#

string url ="http://agratek.dyndns.org:8080/webservice?Op=Actuate&NodeID=2&PortID=0&Value=ON";
System.Net.WebClient myWebClient = new System.Net.WebClient();
Stream myStream = myWebClient.OpenRead(url);
StreamReader sr = new StreamReader(myStream);
string returnData = sr.ReadToEnd(); // check for OK
myStream.Close();

Posted 4-Dec-14 16:16pm

DamithSL

Updated 7-Dec-14 17:10pm

v3

Comments

Gordon Minns 7-Dec-14 16:09pm

Solution 1 give the error message: No overload for method 'OpenRead' takes 0 arguments. Thanks for your answer.

DamithSL 7-Dec-14 23:10pm

Oh sorry , need to give the url,how I missed that!

Gordon Minns · Answer 2 · 2014-12-07T10:29:00

I came up with this solution that works. The button is defined in the .aspx file:

<asp:button id="butValve0_ON" runat="server" onclick="butValve0_ON_Click" text="Valve 0 ON" width="105px" height="25px" xmlns:asp="#unknown" />

This solution causes the whole page to be refreshed, but it always works. One should add some error and no-response checking to this solution. A TextBox is updated when the WebService responds with "OK".

<pre>        protected void butValve0_ON_Click(object sender, EventArgs e)
        {
            //Send the URL to remote server, wait for and capture response
            Uri myUri = new Uri("http://agratek.dyndns.org:8080/webservice?Op=Actuate&NodeID=2&PortID=0&Value=ON");
            System.Net.WebClient myWebClient = new System.Net.WebClient();
            Stream myStream = myWebClient.OpenRead(myUri);
            StreamReader sr = new StreamReader(myStream);
            string returnData = sr.ReadToEnd(); // check for OK
            tbValve0State.Text = returnData;
            myStream.Close();

            if ( returnData.Contains("OK") )
            {
                tbValve0State.Text = "ON";
                tbValve0State.BackColor = System.Drawing.Color.LightGreen;
            }

        }