loading php after pressing a button on same page

Question

1.00/5 (1 vote)

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HTML

<!DOCTYPE html>
<html>
<head>
<script src='http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js'></script>
<script>
  $(document).ready(function(){
  $('.myButton').click(function() {
    var $ct = $(this).next("div.container");
    if (this.value == 'collapse') {
  this.value = 'expand';
  $ct.hide("slow");
 $('.myButton').parent().show("slow");
    } else {
  this.value = 'collapse';
  $ct.show("slow");
 $('.myButton').not($(this)).parent().hide("hide");
    }

  });
});
</script>
</head>
<body>
<?php
for($i=0;$i<=3;$i++)
{
echo"<div class='main' style='removed:relative;border:1px solid #A5BEBE;background-        color:#E7EFEF;width:84%;  '> 
 sometext:-<a href='#'>$url</a><br>
sometext :$b<br>
</p>
<input type='button' value='expand' class='myButton'  name='button1' target='".$i."'       onclick='clickButton(this)'        style='position:absolute;left:85%;top:4%;background:#B20000;color:white;width:70px;height:20px;font-        size:15px;' >";

echo "<div  class='container'  style='display:none;background:white; '>
   sometext:-<a href='#'>$url</a><br>
sometext :$b<br>
sometext :$c<br>
</p>";
if(isset($_GET['button1']))
{ 
echo"<script>alert('msg1');</script>";
include('function.php'); 
} 
echo "</div>";
echo "</div>";
}
?>
</body>
</html>

we are creating four buttons in a for loop with same name and id , if we press even a single button out of four FUNCTION.PHP should be called and executed . for this we have used isset function but its not working.

Posted 11-Dec-14 19:14pm

Member 11107959

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Comments

Sergey Alexandrovich Kryukov 12-Dec-14 1:33am

What exactly do you mean by "not working"?
—SA

Member 11107959 12-Dec-14 2:18am

their is an alert in function.php which is not been called

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