How to create XML file using T-SQL in below format

Question

0.00/5 (No votes)

See more:

I am using this query,

SELECT HEAD.ID AS "HEAD/@ID",
HEAD.CODE AS "HEAD/CODE",
CONVERT(VARCHAR,HEAD.DATE,112) AS "HEAD/DATE",
HEAD.DOCNO AS "HEAD/DOCNO",
ITEM.SERIAL AS "HEAD/ITEM/@ID",
ITEM.ITEMNO AS "HEAD/ITEM/ITEMNO",
ITEM.UOM AS "HEAD/ITEM/UOM",
ITEM.QTY AS "HEAD/ITEM/QTY"
FROM PRODUCT_HDR HEAD, PRODUCT_DTL ITEM
WHERE HEAD.CODE = ITEM.CODE AND HEAD.DATE = ITEM.DATE
FOR XML PATH ('IDOC'), ELEMENTS;

to get result in below format, but its not working.

XML

<?xml version="1.0" encoding="utf-8" ?>
<HEAD ID="1">
  <CODE>001</CODE>
  <DATE>20141208</DATE>
  <DOCNO>2001500000001</DOCNO>
  <ITEM ID="1">
    <ITEMNO>10001</ITEMNO>
    <UOM>KG</UOM>
    <QTY>10.000</QTY>
  </ITEM>
  <ITEM ID="2">
    <ITEMNO>10002</ITEMNO>
    <UOM>KG</UOM>
    <QTY>20.000</QTY>
  </ITEM>
  <ITEM ID="3">
    <ITEMNO>10003</ITEMNO>
    <UOM>KG</UOM>
    <QTY>30.000</QTY>
  </ITEM>
</HEAD>

Posted 24-Dec-14 2:28am

Jyoti Nailwal

Add a Solution

2 solutions

Solution 1

Your data in SQL organised in rows like this:

head1	item1
head1	item2
head1	item3
head2	item1
head2	item2

and so on...

But your XML reflects a structure like this...

head1	item1	item2	item3
head2	item1	item2

This is a structure SQL can not handle...

Posted 24-Dec-14 2:50am

Kornfeld Eliyahu Peter

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Jyoti Nailwal · Accepted Answer · 2014-12-26T17:29:00

I got the solution. Its right below,

SELECT HEAD.ID AS "HEAD/@ID",
HEAD.CODE AS "HEAD/CODE",
CONVERT(VARCHAR,HEAD.DATE,112) AS "HEAD/DATE",
HEAD.DOCNO AS "HEAD/DOCNO",
(SELECT ITEM.SERIAL AS "@ID",
ITEM.ITEMNO AS "ITEMNO",
ITEM.UOM AS "UOM",
ITEM.QTY AS "QTY"
FROM PRODUCT_DTL ITEM
WHERE HEAD.CODE = ITEM.CODE AND HEAD.DATE = ITEM.DATE
FOR XML PATH ('ITEM'), TYPE, ELEMENTS) AS "HEAD"
FROM PRODUCT_HDR HEAD
FOR XML PATH ('IDOC'), ELEMENTS;