why p value comes different on entering 0 or 2 digit number

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C#

#include<stdio.h>
int main()
{
int a=10,*p=&a;
printf("%u\n%u\n%u\n%u\n",&p,&a,p,*p);
scanf("%d",p);
//scanf("%p",p);
printf("%d..%d\n%d\n%u\n",*p,p,a,&p);
}
~
~

Posted 21-Jan-15 7:07am

Member 11389221

Updated 21-Jan-15 7:08am

v2

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CPallini · Answer 1 · 2015-01-21T07:38:00

Solution 1

You are printing different things in the two different printf statements and you are the wrong format specifiers. It should be:

C

#include<stdio.h>
int main()
{
  int a=10,*p=&a;
  printf("%p\n%p\n%p\n%d\n",&p,&a,p,*p);
   if ( scanf("%d",p) != 1 ) return -1;
  //scanf("%p",p);
  printf("%d..%p\n%d\n%p\n",*p,p,a,&p);
  return 0;
}

Posted 21-Jan-15 7:38am

CPallini

Updated 21-Jan-15 7:39am

v2

Comments

Member 11389221 21-Jan-15 17:19pm

thanks for the answer ,but i need to ask if i use %d ,so according to u %d format specifier prints different value because this crosses th limit of the particular format specifier?