radio button change fadeOut and fadeIn didn't work

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$(document).ready(function () {

    $("input[name='Round_trip']").on('click', function () {
        console.log("changed");
        if ($("input[name='Round_trip']:checked").val() === 'false')
            $("#returnFlightInfo").fadeOut();//this didn't work
        else
            $("#returnFlightInfo").fadeIn();//this didn't work

        console.log($("input[name='Round_trip']:checked").val());
//the console.log indeed show change and the value is correct
    });

})

Posted 9-Feb-15 14:04pm

SandyZhang2014

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Santosh K. Tripathi · Answer 1 · 2015-02-09T16:49:00

Solution 1

put these lines in if and else part.

console.log("if part True");
console.log("else part True");

by using following line check, are you able to access #returnFlightInfo

console.log($(#returnFlightInfo).innerHTML());

Posted 9-Feb-15 16:49pm

Santosh K. Tripathi

Comments

SandyZhang2014 9-Feb-15 23:38pm

console.log($(#returnFlightInfo).innerHTML()); show error, say .innerHTML() is not function

SandyZhang2014 9-Feb-15 23:41pm

changed
SydneyValidation.js:104 false
SydneyValidation.js:106
<div class="col-lg-4">
<div class="form-group has-feedback">
<label class="control-label">Return flight #</label>
<input class="form-control" id="Return_Flight_Number" name="Return_Flight_Number" placeholder="Flight Number" type="text" value="" data-bv-field="Return_Flight_Number">
Please enter your return flight number</div>
</div>

<div class="col-lg-4">
<div class="form-group has-feedback">
<label class="control-label">Date</label>
<input class="form-control" data-val="true" data-val-date="The field Return_Flight_Date must be a date." id="datetimepickertimereturnDate" name="Return_Flight_Date" placeholder="Flight Date" type="text" value="" data-bv-field="Return_Flight_Date">

Please select your return flight date</div>
</div>

<div class="col-lg-4">
<div class="form-group has-feedback">
<label class="control-label">Time</label>
<input class="form-control" id="datetimepickertimereturnTime" name="Return_Flight_Time" placeholder="Flight Time" type="text" value="" data-bv-field="Return_Flight_Time">

Please select your return flight time</div>
</div>

The console show correct, but still won't hide

SandyZhang2014 9-Feb-15 23:44pm

I just don't get it, it is very simple jQuery function fadeOut and fadeIn,and console show info is correct,but fadeOut and fadeIn won't work

Peter Leow · Answer 2 · 2015-02-09T17:13:00

Check this out:

<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function () {
 
    $("input[name='Round_trip']").on('click', function () {
        
        if ($("input[name='Round_trip']:checked").val() === 'hide')
            $("#returnFlightInfo").fadeOut();
        else
            $("#returnFlightInfo").fadeIn();

        echo($("input[name='Round_trip']:checked").val());
    });
})
</script>
</head>
<body>
<input type="radio" name="Round_trip" value="show" checked>Show
<input type="radio" name="Round_trip" value="hide">Hide
<br>
<p id="returnFlightInfo">Return Flight Info...</p>

</body>
</html>