Form1 had one button if we click that button it wil show another form(Form2)

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and my question is when ever we click on button previous form 2 be closed and new form2 should be open how to write code in windows forms

thanksss

Posted 15-Feb-15 18:04pm

Parazival

Updated 15-Feb-15 18:08pm

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Pankaj Bhandari08 · Answer 1 · 2015-02-15T18:22:00

Solution 1

Add the following code for the button click event You can also use this.Close to close the form if you don't wish to use it later.

C#

private void button1_Click(object sender, EventArgs e)
        {
            Form2 objForm2 = new Form2();
            objForm2.Show();
            this.Hide();
        }

Posted 15-Feb-15 18:22pm

Pankaj Bhandari08

Comments

Parazival 16-Feb-15 0:38am

it,s hiding form1
but if i open one more time form1 and click on button it will show another form(form2) and previous form2 also available

Pankaj Bhandari08 16-Feb-15 1:09am

so you want like only one instance of form2 should be open?

Parazival 16-Feb-15 1:22am

yes

Pankaj Bhandari08 16-Feb-15 1:36am

I am assuming that you have some MDI from where you are opening the form1,
Create object of form2 on the MDI.

Form2 objForm2 = null;

now on the button click of the form1, first check for if objForm2 is null or not .

if(objForm2 == null)
{
//Create the form2 object and show it.
Form2 objForm2 = new Form2();
}
if(!objForm2.Visible)
{
//we have the form but visiblity is hidden
objForm2.Visible = true
}