sending a data frame

Question

0.00/5 (No votes)

See more:

good evening,
I am trying to develop an application allows me to create an automation system.
I have a little problem about an order; the operator will input a decimal number eg 100000 which is in hex 0x186A0 so just divide it into 3 parts 0x01 0x86 0xA0
can you help me to advance in my project ?
You will find attached the program code:

C++

#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <iostream>
#include <string>        
#include <sstream> 
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
	uint16_t res1 = 0xFFFFFF;
	int D = 0;
	uint8_t tab[3];
	printf("donner valeur decimal: ", D);
	cin >> D;
	std::stringstream ss;
	ss << std::hex << D;
	std::string res(ss.str());
	std::cout << res;

	res1 = (uint16_t)res.c_str();
	
	tab[0] = res1 & 0xFF;
	printf("\n val 1: %x", tab[0]);
	tab[1] = (res1 & 0xFF, res1 >> 8) ;
	printf("\n val 2: %x", tab[1]);
	tab[2] = (res1 & 0xFF, res1 >> 16);
	printf("\n val 3: %x", tab[2]);

	return 0;
}

Posted 23-Feb-15 10:06am

Member 11441147

Updated 23-Feb-15 10:17am

CPallini

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2015-02-23T10:30:00

Solution 1

You may just use a union:

C++

#include <iostream>
#include <stdint.h>

union IntByte
{
  uint32_t i;
  uint8_t b[4];
};

int main()
{
  IntByte ib;

  std::cout << "donner valeur decimal: ";
  std::cin >> ib.i;

  for (int i=0; i<3; ++i)
  {
    std::cout << "val[" << i << "] = " << std::hex << (uint32_t) ib.b[2-i] << std::endl;
  }
}

Posted 23-Feb-15 10:30am

CPallini

Updated 23-Feb-15 10:31am

v2

Comments

Member 11441147 23-Feb-15 16:42pm

thank you ! it work :D

CPallini 24-Feb-15 3:36am

You are welcome.

Sergey Alexandrovich Kryukov 23-Feb-15 18:25pm

Sure, a 5.
—SA

CPallini 24-Feb-15 3:36am

Thank you.