Is there any way to get RGB value from ColorDialog in WPF?

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Hi Friends,

Is there any way to get the RGB value from ColorDialog in WPF?

I have tried following code but but here i'm getting error as

Error	4	Cannot implicitly convert type 'System.Drawing.Color' to 'System.Windows.Media.Color'

Code :

C#

System.Windows.Forms.ColorDialog cd = new System.Windows.Forms.ColorDialog();
 Color clr = cd.Color;

Thanks

Posted 25-Feb-15 2:13am

Znaneswar K

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2 solutions

Solution 2

The Color class has properties

C#

public byte R { get; }
public byte G { get; }
public byte B { get; }

This snippet shows how to get the RGB values:

C#

ColorDialog cd = new ColorDialog();

DialogResult result = cd.ShowDialog();

if (result == DialogResult.OK)
{
    Color color = cd.Color;

    byte R = color.R;
    byte G = color.G;
    byte B = color.B;
}

Posted 25-Feb-15 3:00am

TheRealSteveJudge

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Richard Deeming · Accepted Answer · 2015-02-25T03:34:00

Solution 3

Cannot implicitly convert type 'System.Drawing.Color' to 'System.Windows.Media.Color'

The problem is that you're using the Windows Forms ColorDialog, which returns a System.Drawing.Color, whereas WPF tends to use System.Windows.Media.Color.

You could switch to using a WPF colour picker - for example, this one[^].

Alternatively, you'll need to convert the returned colour:

C#

var cd = new System.Windows.Forms.ColorDialog();
...
var winFormsColor = cd.Color;
var wpfColor = System.Windows.Media.Color.FromArgb(winFormsColor.A, winFormsColor.R, winFormsColor.G, winFormsColor.B);

Posted 25-Feb-15 3:34am

Richard Deeming

Comments

Znaneswar K 26-Feb-15 4:29am

I have tried this one but still I'm getting the same error :( Any other ways?

Thanks

Richard Deeming 26-Feb-15 7:08am

You won't be getting the same error from the code I posted - there's no attempt to assign a System.Drawing.Color to a System.Windows.Media.Color.

Either you're getting a different error, or you've changed the code.

Znaneswar K 26-Feb-15 7:24am

Sorry I confused. its working fine now :)

Thanks a lot.