Dear All Of Sir.How I Login From Android Project Into Localhost Webservice(Http://127.0.0.1:8083/Myservice.Svc/Login?Username=Admin&Password=Ace).But I Face Errors.Sir.Thanks .Help Me

Question

0.00/5 (No votes)

See more:

My Code are Here!
http://127.0.0.1:8083/MyService.svc/Login?UserName=admin&Password=ace[^]

this address retrun true.

C#

public void CheckUserNameandPwd() {
      // TODO Auto-generated method stub
      String  username = u.getText().toString().trim();
      String  pwd=pwdd.getText().toString().trim();
      if(username.length()==0){
          AlertDialog.Builder dlgAlert  = new AlertDialog.Builder(this);
          dlgAlert.setMessage("Fill UserName!");
          dlgAlert.setTitle("Error");
          dlgAlert.setPositiveButton("OK", null);
          dlgAlert.setCancelable(true);
          dlgAlert.create().show();
          return;
      }
      else if(pwd.length()==0 ){
          AlertDialog.Builder dlgAlert  = new AlertDialog.Builder(this);
          dlgAlert.setMessage("Fill Password!");
          dlgAlert.setTitle("Error");
          dlgAlert.setPositiveButton("OK", null);
          dlgAlert.setCancelable(true);
          dlgAlert.create().show();
          return;
      }
      else{
          if(verifyLogin(username,pwd)){
              Toast.makeText(getApplicationContext(),"Login Success",Toast.LENGTH_SHORT).show();
              startActivity(new Intent(Login.this,MainActivity.class));
          }else{
              Toast.makeText(getApplicationContext(),"error occur!",Toast.LENGTH_SHORT).show();
             // startActivity(new Intent(Login.this,mainlayout_activity.class));
          }
      }
  }

  private boolean verifyLogin(String username, String pwd) {
      try{
          showpDialog();
          DefaultHttpClient httpclient=new DefaultHttpClient();
          HttpGet httpget=new HttpGet("http://127.0.0.1:8083/MyService.svc/LoginForUsers?UserName=" + username + "&Password=" + pwd);
          HttpResponse httpresponse=httpclient.execute(httpget);
          HttpEntity httpentity=httpresponse.getEntity();
          InputStream stream=httpentity.getContent();
          String result=ConvertStreamToString(stream);
          if(result.charAt(1)=='1'){
              hidepDialog();
              return  true;
          }else {
              hidepDialog();
              return  false;
          }
      }catch (Exception e){
          hidepDialog();
          return  false;

      }
  }

  private String ConvertStreamToString(InputStream is) {
      BufferedReader reader=new BufferedReader(new InputStreamReader(is));
      StringBuffer sb=new StringBuffer();
     String line=null;
      try
      {
          while ((line=reader.readLine())!=null){
              sb.append(line+"\n");
          }
      }catch (IOException e){
          e.printStackTrace();
      }finally {
          try {
              is.close();
          } catch (IOException e) {
              e.printStackTrace();
          }

      }
      return  sb.toString();
  }

............
but i face this error msg in logcat.

Quote:
username={java.long.String@3773}"admin"
pwd={java.long.String@3775}"ace"
e={android.os.NetworkOnMainThreadException@3806}" android.os.NetworkOnMainThreadExcetpion
cause="android.os.NetworkOnMainThreadExcetpion"
detailMessage=null
staickState={java.lang.Object[32]@3829}
StackTrace={java.lang.StackTraceElement[0]@3830

Posted 16-Mar-15 0:07am

MgKyaing

Updated 16-Mar-15 0:13am

CHill60

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sid_Joshi · Answer 1 · 2015-03-16T00:41:00

@SuppressLint("NewApi")
	public boolean isValid(String UName,String Pswd)
	{
		
		 String msg="";
		
		try {
			StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();				
		    StrictMode.setThreadPolicy(policy);
		    
		    DefaultHttpClient httpClient = new DefaultHttpClient();
		    URI uri = new URI("http://10.0.2.2:13514/Service1.svc/IsValidUser?userid="+UName+"&password="+Pswd); 
		 
		    HttpGet httpget = new HttpGet(uri);
/*		    httpget.setHeader("Accept", "application/json");
		    httpget.setHeader("Content-type", "application/json; charset=utf-8");*/
		 
		    HttpResponse response = httpClient.execute(httpget);
		    HttpEntity entity = response.getEntity();
				BufferedReader in = new BufferedReader(new InputStreamReader(entity.getContent()), 65728);
			      msg = in.readLine();
			      if(msg.contains("success")){

			    	  return true;
			      }
			      else
			      {

			    	  return false;
			      }
		}
		catch(Exception ex)
		{
					Log.v("Tag","error"+ex.getMessage());

					return false;
		}
		
	}

and Dont forget to add

<uses-permission android:name="android.permission.INTERNET" />

in Manifeast file