getting a exception when execute exe on another system

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I am getting this exception when i run my exe on another system?
any suggestion?

Exception Text 
System.ComponentModel.Win32Exception (0x80004005): The system cannot find the file specified
   at System.Diagnostics.Process.StartWithShellExecuteEx(ProcessStartInfo startInfo)
   at System.Diagnostics.Process.Start()
   at EMSAlpha1.Form1.Form1_Load(Object sender, EventArgs e)
   at System.Windows.Forms.Form.OnLoad(EventArgs e)
   at System.Windows.Forms.Form.OnCreateControl()
   at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible)
   at System.Windows.Forms.Control.CreateControl()
   at System.Windows.Forms.Control.WmShowWindow(Message& m)
   at System.Windows.Forms.Control.WndProc(Message& m)
   at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
   at System.Windows.Forms.Form.WmShowWindow(Message& m)
   at System.Windows.Forms.Form.WndProc(Message& m)
   at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)

Posted 18-Mar-15 1:24am

Aditya Chauhan

Updated 18-Mar-15 1:29am

RajeeshMenoth

v2

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manchanx · Answer 1 · 2015-03-18T01:30:00

Solution 1

You're starting some external program in your Form1.Form1_Load(..)-Method via ShellExecute. And that program apparently doesn't exist on the other system or is located in a different path.

Posted 18-Mar-15 1:30am

manchanx

Comments

Sergey Alexandrovich Kryukov 18-Mar-15 7:33am

5ed. Please see also my a bit more detailed answer.
—SA

[no name] 18-Mar-15 7:44am

Thank you, Sergey!
это приемлемо, если я обращаюсь к вам, только с вашим именем?
- Себастьян

Sergey Alexandrovich Kryukov 18-Mar-15 7:54am

You are welcome.
Sure, good enough (especially in English :-). I'm often called "SA", this is perfectly fine.
—SA

[no name] 18-Mar-15 7:57am

Alright :-) I spotted a comment from you which made me think about russian naming conventions again ;-)

Sergey Alexandrovich Kryukov 18-Mar-15 8:29am

Perhaps it was using full name in low-case, which is very inappropriate in many cultures...
—SA

Aditya Chauhan 18-Mar-15 7:34am

in the form section i started a new process but it is running in my system;
and i have also give the same path in the that system?
means my exe is at the same path

[no name] 18-Mar-15 7:46am

I'd suggest you double-check that. The exception message is quite unambiguous.

Sergey Alexandrovich Kryukov 18-Mar-15 7:55am

No assumptions like that should be made. Another problem could be permissions. The file can be invisible for the application.
—SA

Sergey Alexandrovich Kryukov · Answer 2 · 2015-03-18T01:33:00

The reason for the exception: you make false assumption that some file which exists on your particular system should be present on all systems.

Solution:

Learn how OS works and never rely on existence and predefined locations of any files. Know all ins and outs of your own code. Everything should be based on some path calculations. In particular, please see my past answers:
How to find my programs directory (executable directory),
How to find my programs directory (current directory, "special folders").

There are no cases when hard-coded file path can be used. File names can be supplied be the users, defined in some configuration files, and so on. Your code should check up System.File.Exists before opening a file, stream or StreamReader.

—SA