Setting JSON data into variables in PHP using AJAX

Question

1.00/5 (1 vote)

See more:

Hi,

Using the twitter API twitteroauth, I retrieved credentials in json format as shown below:

{"oauth_token":"XXXXXXXXXXXXXXXXXXXXXXX","oauth_token_secret":"XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX","user_id":"123456789","screen_name":"myTwitterUsername"}

How would I use AJAX to get the user_id and screen_name from the JSON results above and store them into seperate variables in PHP so that they can be used on the UI?

Posted 8-May-15 7:04am

jba1991

Add a Solution

Comments

Sergey Alexandrovich Kryukov 8-May-15 13:35pm

Why Ajax? Haven't you already got the JSON string on the server side? Anyway, do you want to retrieve it on server side or client side?
—SA

jba1991 9-May-15 8:00am

I have used json_encode on a variable and echo'd the variable which displays the data on the client side (it is displaying the line of code from the question in the browser).

I just want to be able to get each part of the json encoded data shown in the question and store them into their own variable, so I can echo something like "welcome, $sceen_name" and store it in a PHP session

jba1991 9-May-15 16:53pm

Can anyone help?

Sergey Alexandrovich Kryukov 9-May-15 20:03pm

And what, you did not even notice the answer of yesterday?
—SA

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sergey Alexandrovich Kryukov · Accepted Answer · 2015-05-08T07:37:00

Solution 1

The question is not clear enough, but it's possible that you just need PHP json_decode:
http://php.net/manual/en/function.json-decode.php[^].

—SA

Posted 8-May-15 7:37am

Sergey Alexandrovich Kryukov

Comments

jba1991 10-May-15 7:14am

I just read this wrong as json_encode not json_decode, so apologies for that. I've tried json_decode($json) with $json being my json formatted data, but nothing changed.

jba1991 10-May-15 7:30am

json_decode() expects parameter 1 to be string, array given

I am getting this error when using json_decode. I am aware that that json encoded data is in an array, how do I convert this to a string before decoding?

Sergey Alexandrovich Kryukov 10-May-15 10:49am

The parameter should be the string, yes. In your, sample, this is not an array, this is some object which does not need deserialization.
—SA

jba1991 10-May-15 7:45am

I currently have this value returning using var_dump(json_decode($json, true));

array(4) { ["oauth_token"]=> string(50) "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX" ["oauth_token_secret"]=> string(45) "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX" ["user_id"]=> string(10) "123456890" ["screen_name"]=> string(8) "username" }

Is this correct?