display image from database by name

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I have database

PHP

`image_name`, `caption`, `image`, `username`

I want to display the image according his name in database(image_name)I have this code the error in it the image is not show

PHP

<?php

 require_once("db.php");
 session_start();
 $username = $_SESSION['username'];
 $sql = "SELECT * from photo2 WHERE Username='$username'";
 $result = mysql_query($sql) or die (mysql_error());
 $numrows = mysql_num_rows ($result);
 if($numrows!=0)
   {
  while ($found_ids = mysql_fetch_assoc($result))
  {

  echo "<tr><td align='center'> $found_ids[image_name]</a></td>  </tr>";
      //echo "<img src=get.php?id=$found_ids[ID]";
   }
}

$id = addslashes($_REQUEST['image_name']);
$image = mysql_query("SELECT * FROM photo2 WHERE image_name=$id");
$image = mysql_fetch_assoc($image);
$image = $image['Photodata'];

header ("Content-type: image/jpeg");
echo $image;

?>

Posted 25-May-15 7:49am

neveen neveen

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Mohibur Rashid · Answer 1 · 2015-05-25T12:21:00

you have very little knowledge of HTTP protocol.
Remove the last ?>

->You cannot print header after sending out html data.

->Your session should start ahead of including db.php

->you cannot send HTML data while you are sending image data. HTTP protocol did not stablish anything to achieve this.

->You have two distinct method POST or GET, using REQUEST is a bad idea.

to send image two methods can be used.

i) Convert the image into base64 encoded text and attach it with your html code. example(taken from wikipedia):

HTML

<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot" />

look "base64_encode" up

ii) second method is simpler: save the string in a file as image. then create the image link with the path. Example:

HTML

<img src="<?=$path?>" >