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Because the sting you are passing isn't a valid path so your program thinks it is a relative path and appends it to the current directory of your application.
Giorgi Dalakishvili
#region signature
my articles
#endregion
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Hi,
Thanks for the responses. However, c:\projects does exist on my PC and I have also tried @c:\\projects but am still getting the same problem. However if I hard code as in the following it works fine.
XMLDoc.Save(@"c:\projects\text.xml")
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May be it is taking what you gave in the xmlDoc.FileName as the FILENAME and not the actual path. So the batch will be now [Default solutionpath]\FileName.
In the lter case the Save accepts the actuall path to the file and works fine.
May be you can try storing the path differently nad get it to the scene only in the save function
Thanks
Laddie
Kindly rate if the answer was helpful
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c:\projects is a folder, not a file so how can xmlwriter write to it? You need to specify file path. If you need to path of folder for something else try this: @C:\projects\
Giorgi Dalakishvili
#region signature
my articles
#endregion
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Simple problem. See if you can spot the difference:
xmloutput.FileName = @"c\projects\text.xml";
xmloutput.FileName = @"c:\projects\text.xml";
In essence the path you specified is not what you had intended. You meant to specify an absolute path. The compiler didn't detect the drive (c and treats the whole thing as path relative to wherever the application is being run from. In your case the bin\Debug.
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hi
i added a combobox and dateTimePicker in datagrid columns.These controls are working properly.But whenever any value is selected from these controls, the datagrid is not get edited.i mean that no new row is added to datagrid,hence the datagrid is appearing with one row only.There are 3 columns in datagrid two with comboboxes and one DateTimePicker.
how to solve this problem?
here is the code i had written
sFromCb=new ComboBox();<br />
sFromCb.Cursor = System.Windows.Forms.Cursors.Arrow;<br />
sFromCb.DropDownStyle = ComboBoxStyle.DropDownList;<br />
sFromCb.Width = 100;<br />
sFromCb.SelectionChangeCommitted +=new EventHandler(sFromCb_SelectionChangeCommitted);<br />
<br />
DataGridTextBoxColumn fromcol=new DataGridTextBoxColumn();<br />
fromcol.MappingName = dtCore.Columns[i].ColumnName; <br />
fromcol.HeaderText = fromcol.MappingName;<br />
fromcol.Width=100;<br />
fromcol.ReadOnly=true;<br />
fromcol.TextBox.Enter +=new EventHandler(fromcolTextBox_Enter);<br />
fromcol.TextBox.Leave +=new EventHandler(fromcolTextBox_Leave);<br />
fromcol.TextBox.Controls.Add(sFromCb);<br />
tableStyle.GridColumnStyles.Add(fromcol);<br />
<br />
private void sFromCb_SelectionChangeCommitted(object sender, EventArgs e)<br />
{<br />
dataGrid1[dataGrid1.CurrentCell] = ((ComboBox)sender).SelectedItem.ToString(); }<br />
<br />
private void fromcolTextBox_Enter(object sender, EventArgs e)<br />
{<br />
((TextBox)sender).Visible=true;<br />
sFromCb.SelectedItem=((TextBox)sender).Text;<br />
sFromCb.Focus();<br />
}<br />
private void fromcolTextBox_Leave(object sender, EventArgs e)<br />
{<br />
((TextBox)sender).Text=dataGrid1[dataGrid1.CurrentCell].ToString();<br />
((TextBox)sender).Visible=false;<br />
}The items in combobox is coming from a dataset.
Thanks in advance for help
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hello
i want to add submit button on grid view control.
pls tell me code.
gayatri
Gayatri
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Submit to where?
Changes are always written to the DataSource, but that doesn't mean that they are written to the database or file that the data comes from. That you have to write code for. If this is what you want to do you must be more specific on what the source is. There is also a lot of examples on how to do this on MSDN and internet.
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thanku sir
sir i want button in one column.
when i click on that button that time the values are display on textbox etc.
so pls help me.
gayatri
Gayatri
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I'm looking for a working FTP server class / code in C#, preferably without interface. Any help would be great.
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Please help me how do i c orrect this errors
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easy, switch off the computer, unplug it, pack it back into the box it came in, take it back to the store and tell them you're not allowed to own a computer.
Or, read this[^] and pay attention to the section on error messages.
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Hi all,
I have a form and there is a combobox on it. I pass some values to a function in another class for example:
...
public void ODBCBindControls(Control.ControlCollection collection, BindingSource source)
...
I then want to set the DataSource and the DisplayMember of the combobox in the function mentioned above collection[x]. But I cannot get hold of the two properties. Why is this? Is there a way around it, or am I trying something that is desirable?
Many thanks in advance
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's ![Green Alien | [Alien]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/alien.gif)
Programm3r
My Blog: ^_^
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Well this works ...
...
ComboBox box = (ComboBox)collection[c];
box.DataSource = source;
box.DisplayMember = "COID";
...
The only programmers that are better that C programmers are those who code in 1's and 0's
Programm3r
My Blog: ^_^
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You always need to cast the object to the correct type to be able to access specific properties. So this way is the only way.
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Thanks for the advice Christian.
I do something like this:
...
Type controlType = collection[c].GetType();
switch (controlType.FullName)
{
case "System.Windows.Forms.ComboBox":
...
}
...
Thanks
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's
Programm3r
My Blog: ^_^
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Or...
if (collection[c] is System.Windows.Forms.ComboBox)
{
...
}
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In C# , I have upload data from CSv file to SQL Table without using CsvDataReader. is there a way to do this?
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Why can't you use CsvDataReader? One alternative would be a combination of StreamReader and the String.Split method.
He who makes a beast out of himself gets rid of the pain of being a man
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Yes,
csv to dataset
dataset to Database
CP[^]
Google[^]
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hi
What is the way to check for empty arraylist?..any one can help me ?
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Check the .Count property.
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yaa...i tried...but it is throwing an exception....
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Probably your ArrayList is not created yet. Check if it's null first. Not created is not the same as empty.
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