C#

George_George wrote:

For code like this,

struct Foo
{
public int abc;
}

Is there a default constructor generated which is parameter-less?

L_0000: ldloca.s x<br />
L_0002: initobj Foo

Guffa wrote:

George_George wrote:
1. For value type, whether or not we provide a customized constructor, there is a default one (co-exist with customized one).



No,

S. Senthil Kumar wrote:

Actually yes, there is always the default parameterless constructor, regardless of whether you overload it or not.

George_George wrote:

1. For value type, even if we provide a customized constructor, there is also the default one (co-exist with customized one)?

George_George wrote:

2. For reference type, there is also a default constructor even if we provide a customized one (co-exist with default one)?

S. Senthil Kumar wrote:

"If no instance constructor is supplied for a class, then an empty one with no parameters is automatically provided."

George_George wrote:

And even if we provide a customized one, the default parameter-less one still exists.

class S
{
    int x;
    public S(int x)
    {
        this.x = x;
    }

    public int X
    {
        get { return x; }
    }
}
class Program
{
    static void Main(string[] args)
    {
        S s = new S();
        Console.WriteLine(s.X);
    }
}

StructValueType abc;

George_George wrote:

the memory for new instance of abc is actually allocated even if we do not use new + constructor explicitly

George_George wrote:

StructValueType abc;

George_George wrote:

So, for statement like below, the memory for new instance of abc is actually allocated even if we do not use new + constructor explicitly. But for reference type, without using new, no instances' space are allocated. Correct?

S. Senthil Kumar wrote:

so stack space will be reserved right away.

George_George wrote:

And even if we provide a customized one, the default parameter-less one still exists.

class Program
{
   static void Main(string[] args)
   {
      Foo foo = new Foo();
   }
}
class Foo
{
   public Foo(int param)
   {
   }
}

George_George wrote:

for value type, it exists and for reference type it does not exists. Right?

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