C#

int num = 1000;
byte one = (byte)(0x00FF & num);
byte two = (byte) ((0xFF00 & num) >> 8);

Exception System.OverflowException was thrown in debuggee:
Arithmetic operation resulted in an overflow.

int n = 1000;
System.Diagnostics.Debug.WriteLine((byte)n); // 232
System.Diagnostics.Debug.WriteLine((n >> 8)); // 3

int n = 1000;
byte i = (byte)n;

int n = 1000;
byte i = (byte)n;
System.Diagnostics.Debug.WriteLine(i);

George_George wrote:

For value type, even if we provide a customized constructor, there is also the default one (co-exist with customized one)?

George_George wrote:

For reference type, there is also a default constructor even if we provide a customized one (co-exist with default one)?

ForumExpertOnLine wrote:

George_George wrote:
For value type, even if we provide a customized constructor, there is also the default one (co-exist with customized one)?

NO

struct S
{
    int x;
    public S(int x)
    {
        this.x = x;
    }

    public int X
    {
        get { return x; }
    }
}
class Program
{
    static void Main(string[] args)
    {
        S s = new S();
        Console.WriteLine(s.X);
    }
}