Problem with variables and SUM

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I have this:

C#

for(i=1; i<= num; i++)
    {
     
      loadNotes(resultado[i],resultado[i+num],pos_x,pos_y);
      pos_x = pos_x+200;
      //pos_y = pos_y+250;
      pos_y = 0;
    }
}

The problem is: "i+num" are not being seen as a SUM but as a concat (.).

i.e., lets suppose that num = 5 and for i=1

instead resultado[i+num] = resultado [6] its happening resultado[15].

num and resultado[], are string and array of strings, comes from C#, I really need that way, so I'm wondering how can I solve this problem.

I cant parse the whole array because half of it are really strings

Posted 23-Dec-10 5:19am

Maxdd 7

Updated 23-Dec-10 5:27am

v4

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3 solutions

Solution 3

Based on your previous questions num is being returned from the server as a string so JavaScript, a loosely typed language, is interrupting the action as a string concatenation and converting i to a string thus producing 15 rather than the 6 you are expecting.

You can either change your server code to return an int or use parseInt in the JavaScript

Also, based on your previous questions I would strongly suggest you pick up a book on JavaScript and read it before continuing.

Posted 23-Dec-10 5:31am

Not Active

Comments

Maxdd 7 23-Dec-10 11:32am

You are absolutely right!

Solution 4

How about parsing into a new variable?

var mySum = parseInt(i) + parseInt(num)

loadNotes(resultado[i],resultado[mySum],pos_x,pos_y);

Having javascript understand that these are numbers is the only it's going to understand you want to perform a mathmatical operation on them.

Posted 23-Dec-10 5:33am

Dylan Morley

Updated 23-Dec-10 5:36am

v2

Comments

[no name] 23-Dec-10 16:37pm

Since i is already an integer why would you need to use parseInt(i)?

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E.F. Nijboer · Accepted Answer · 2010-12-23T05:31:00

Solution 2

Simply surround the string types with parseInt(num) to cast it to an integer number. You could also use parseFloat. You need to parse all the string types that should actually be a number.

Try this:

loadNotes(parseInt(resultado[i]),parseInt(resultado[parseInt(i)+parseInt(num)])),pos_x,pos_y);

Good luck!

Posted 23-Dec-10 5:31am

E.F. Nijboer

Comments

Maxdd 7 23-Dec-10 11:33am

That's what I did :)