Deserializing Json Response into object

Question

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Hi All,

I am using CloudMade Api for using maps. This Api is returning Json result as Below:

{"places":[{"addressType":"street","city":"~Slough","country":"United Kingdom","featureType":"Ortsstrasse","position":{"lat":51.51465939,"lon":-0.58932440},"state":"England","street":"Adrians Walk","zip":"SL2 5AT"},{"addressType":"sight","city":"~Slough","country":"United Kingdom","featureType":"Building a terrain of interest","name":"Slough","position":{"lat":51.51206867,"lon":-0.59121503},"state":"England","street":"Railway Terrace"},{"addressType":"sight","city":"~Slough","country":"United Kingdom","featureType":"Station","name":"Slough","position":{"lat":51.51225777,"lon":-0.59193386},"state":"England","street":"Railway Terrace"}],"status":{"duration":636,"procedure":"geo.location.search.2","success":true}}

I want to de-serialize this response into object. I am currently using following object.
but it is throwing error "Cannot deserialize JSON object into type 'OpenstreetMap.places[]'."

public class places
{
public string addressType { get; set; }
public string city { get; set; }
public string country { get; set; }
public string featureType { get; set; }
public List<object> position { get; set; }
public string state { get; set; }
public string street { get; set; }
public string zip { get; set; }
public List<object> status { get; set; }
}

And I am using below code for this:

XML

string s =@"http://beta.geocoding.cloudmade.com/v3/0552b29114ef41a4ac10d06bf97939b4/api/geo.location.search.2?format=json&source=OSM&enc=UTF-8&limit=10&locale=en&q=24%20adrians%20walk,%20slough";
           var client = new RestClient(s);
           var request = new RestRequest(s);
           RestResponse response = client.Execute(request) as RestResponse;
           var json = response.Content; // raw content as string
           places[] obj = JsonConvert.DeserializeObject<places[]>(json);

Thanks

Umesh Tayade

Posted 30-Sep-13 22:51pm

Umesh Tayade

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Comments

Kornfeld Eliyahu Peter 1-Oct-13 4:58am

The answer you got is an object with two properties
1. places - an array of objects
2. status - a single object
You try to deserialize it as status is property of places...

Umesh Tayade 1-Oct-13 5:41am

Hi Kornfeld,

Thanks for response.

I tried above code but its not working.
I also tried by modifying my class as below:

public class places
{
[JsonProperty("addressType")]
public string AddressType { get; set; }
[JsonProperty("city")]
public string City { get; set; }
[JsonProperty("country")]
public string Country { get; set; }
[JsonProperty("featureType")]
public string FeatureType { get; set; }
[JsonProperty("position")]
public List<Position> Positions { get; set; }
[JsonProperty("state")]
public string State { get; set; }
[JsonProperty("street")]
public string Street { get; set; }
[JsonProperty("zip")]
public string Zip { get; set; }
}

public class Position
{
public string lat { get; set; }
public string lon { get; set; }
}

public class status
{
public int duration { get; set; }
public string procedure { get; set; }
public bool success { get; set; }
}

public class obJson
{
public places[] places { get; set; }
[JsonProperty("status")]
public status Status { get; set; }
}

obJson obj = JsonConvert.DeserializeObject<objson>(json);

but it is throwing error as "Cannot deserialize JSON object into type 'System.Collections.Generic.List`1[OpenstreetMap.Position]'."

Thanks

Umesh Tayade

2 solutions

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Mehdi Gholam · Answer 1 · 2013-09-30T23:29:00

Solution 1

Try deserializing into the following:

C#

public class alist
{
   public Place[] places;
}
...
var obj = JsonConvert.DeserializeObject<alist>(json);
...
</alist>

Posted 30-Sep-13 23:29pm

Mehdi Gholam

Comments

Umesh Tayade 1-Oct-13 5:41am

Hi Mehdi,

Thanks for response.

I tried above code but its not working.
I also tried by modifying my class as below:

public class places
{
[JsonProperty("addressType")]
public string AddressType { get; set; }
[JsonProperty("city")]
public string City { get; set; }
[JsonProperty("country")]
public string Country { get; set; }
[JsonProperty("featureType")]
public string FeatureType { get; set; }
[JsonProperty("position")]
public List<Position> Positions { get; set; }
[JsonProperty("state")]
public string State { get; set; }
[JsonProperty("street")]
public string Street { get; set; }
[JsonProperty("zip")]
public string Zip { get; set; }
}

public class Position
{
public string lat { get; set; }
public string lon { get; set; }
}

public class status
{
public int duration { get; set; }
public string procedure { get; set; }
public bool success { get; set; }
}

public class obJson
{
public places[] places { get; set; }
[JsonProperty("status")]
public status Status { get; set; }
}

obJson obj = JsonConvert.DeserializeObject<objson>(json);

but it is throwing error as "Cannot deserialize JSON object into type 'System.Collections.Generic.List`1[OpenstreetMap.Position]'."

Thanks

Umesh Tayade

Umesh Tayade · Answer 2 · 2013-09-30T23:46:00

Hi All,

I have solved the aboce issue by modifying my class as given below:

SQL

public class places
    {
        [JsonProperty("addressType")]
        public string AddressType { get; set; }
        [JsonProperty("city")]
        public string City { get; set; }
        [JsonProperty("country")]
        public string Country { get; set; }
        [JsonProperty("featureType")]
        public string FeatureType { get; set; }
        [JsonProperty("position")]
        public Position Positions { get; set; }
        [JsonProperty("state")]
        public string State { get; set; }
        [JsonProperty("street")]
        public string Street { get; set; }
        [JsonProperty("zip")]
        public string Zip { get; set; }
    }

    public class Position
    {
        public string lat { get; set; }
        public string lon { get; set; }
    }

    public class status
    {
        public int duration { get; set; }
        public string procedure { get; set; }
        public bool success { get; set; }
    }

    public class obJson
    {
        public places[] places { get; set; }
        [JsonProperty("status")]
        public status Status { get; set; }
    }

and
obJson obj = JsonConvert.DeserializeObject<objson>(json);

Thanks

Umesh Tayade