Deserialization, value of typeof

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Hello!
I made this code: (visual studio, new project, visual c#, wpf application)

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;

using System.IO;
using System.Xml.Serialization;

namespace lion4
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            Book.MyMain();
        }
    }

    public class Book
    {
        public string Name { get; set; }
        public int ISBN { get; set; }

        public static void MyMain()
        {

            Book book1 = new Book { Name = "Lion4", ISBN = 666 };

            //string bookFileName = "lion4.xaml";

            XmlSerializer serializer = new XmlSerializer(typeof(Book));

            using (TextWriter writer = new StreamWriter(@"Lion4.xml"))
            {

                serializer.Serialize(writer, book1);

            }
        }

    }
}

which creates a xml file lion4.xml (serialized).

Then I tried to use this file to try deserialization, like on this example (just open file, no saving), sth like in this example:

How To Use The XML Serializer & Deserializer in .NET (C#) - YouTube[

Here is my code:
.cs :

C#

using System;
using System.IO;
using System.Windows;
using Microsoft.Win32;
using System.Xml.Serialization;

namespace WpfTutorialSamples.Dialogs
{
    public partial class OpenFileDialogSample : Window
    {
        public OpenFileDialogSample()
        {
            InitializeComponent();
        }

        private void btnOpenFile_Click(object sender, RoutedEventArgs e)
        {
            OpenFileDialog openFileDialog = new OpenFileDialog();
            if (openFileDialog.ShowDialog() == true)
                txtEditor.Text = File.ReadAllText(openFileDialog.FileName);
            MessageBox.Show("Hello, world!", "My App", MessageBoxButton.YesNo, MessageBoxImage.Information);
            
            if (MessageBox.Show("Yes", "No", MessageBoxButton.YesNo) == MessageBoxResult.Yes)
            {
                var path = openFileDialog.FileName;
               XmlSerializer serializer = new XmlSerializer(typeof(Book));
                StreamReader reader = new StreamReader(path);

                var input = serializer.Deserialize(reader);
                button1.Content = input;
            }
        }
    }
}

code in .xaml:

<pre lang="HTML"><Window x:Class="WpfTutorialSamples.Dialogs.OpenFileDialogSample"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="OpenFileDialogSample" Height="300" Width="708">
    <DockPanel Margin="10" Width="651">
        <WrapPanel HorizontalAlignment="Center" DockPanel.Dock="Top" Margin="0,0,0,10">
            <Button Name="btnOpenFile" Click="btnOpenFile_Click">Open file</Button>
        </WrapPanel>
        <TextBox Name="txtEditor" />
        <Button Content="Button" Height="83" Name="button1" Width="592" />
    </DockPanel>
</Window>

The only error is typeot(Book), which in the example video is typeof(List<person>). As the file is still serialized and existing, please, what ttypeof value should I use? MANY THANKS!!!

What I have tried:

XmlSerializer serializer = new XmlSerializer(typeof(Book));

Posted 16-Jun-16 22:16pm

Member 12581582

Updated 17-Jun-16 6:07am

v2

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Comments

Sergey Alexandrovich Kryukov 17-Jun-16 4:18am

Better don't use obsolete XmlSerializer, which was never been good enough, use Data Contract.
—SA

Member 12581582 17-Jun-16 12:00pm

Hello, the point of the tassk is to do it using XmlSerializer... :)

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Member 12581582 · Answer 1 · 2016-06-17T06:04:00

Hello, I tried to simplify if possible:

.cs

<pre lang="c#">using System;
using System.IO;
using System.Windows;
using Microsoft.Win32;

using System.Xml.Serialization;

namespace ofd1
{
    public partial class OpenFileDialogSample : Window
    {
        public OpenFileDialogSample()
        {
            InitializeComponent();
        }


        
        private void btnOpenFile_Click(object sender, RoutedEventArgs e)
        {
            OpenFileDialog openFileDialog = new OpenFileDialog();
            if (openFileDialog.ShowDialog() == true)
                txtEditor.Text = File.ReadAllText(openFileDialog.FileName);

            var path = openFileDialog.FileName;
            XmlSerializer serializer= new XmlSerializer (typeof(Book));
            StreamReader reader = new StreamReader(path);
            var input = Convert.ToString(serializer.Deserialize(reader));

            txtEditor2.Text = input;
        }
    }
}

.xaml

HTML

<window x:class="ofd1.OpenFileDialogSample" xmlns:x="#unknown">
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="OpenFileDialogSample" Height="300" Width="300">
    <dockpanel margin="10">
        <wrappanel horizontalalignment="Center" dockpanel.dock="Top" margin="0,0,0,10">
            <button name="btnOpenFile" click="btnOpenFile_Click">Open file</button>
        </wrappanel>
        <textbox name="txtEditor" width="129" />
        <textbox name="txtEditor2" />
    </dockpanel>
</window>

Now, to get the deserialization in the second textBox, I just need to find the object Book from another project. I did: Solution Explorer- add reference, I found the project map and which one do I have to choose, at this point each I chose is wrong and gives mistake again!!!

Many thanks, please, I am the sheer beginner!!! Try to google but get al I know or does not help with that particular problem!!!