Sqlserver Doubt in Attendance, Time, Date

Question

1.00/5 (3 votes)

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Input :
I am having the table
StaffNo Date Time
12333 12-02-2013 09.30
12333 12-02-2013 17.30

13245 12-02-2013 09.15
13245 12-02-2013 10.10
13245 12-02-2013 17.35

14555 12-02-2013 09.10
14555 12-02-2013 10.40
14555 12-02-2013 11.45
14555 12-02-2013 17.30

Output :

12333 12-02-2013 09.30-17.30
13245 12-02-2013 09.15-10.10,17.35
14555 12-02-2013 09.10-10.40,11.45-17.30

Thanks & Regards,
Nirmal.M

Posted 18-Feb-13 17:11pm

Member 1233140

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Comments

Richard C Bishop 19-Feb-13 15:39pm

You have been a memeber for almost 9 years and you are asking your first question today. What is up with that?

Sergey Alexandrovich Kryukov 9-Apr-13 0:44am

Excuse me, where did you find a question?!
—SA

Richard C Bishop 9-Apr-13 9:40am

No question indeed, should have said first thread.

2 solutions

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*Karthik Harve* · Answer 1 · 2013-02-18T17:33:00

Solution 1

Hi,

try this query,

SQL

SELECT DISTINCT StaffNO, COALESCE(Cast(DateTime As VRACHAR(50)) + '-', '') as 'Time' FROM TableName GROUP BY StaffNo

hope it helps

Posted 18-Feb-13 17:33pm

Karthik Harve

ssd_coolguy · Answer 2 · 2013-02-18T22:20:00

Solution 4

see the below query,
might it helps...

SQL

select a.StaffNo,a.Date, SUBSTRING(b.alltime ,1, LEN(b.alltime ) - 1) from 
(select distinct StaffNo, Date from tablename) A cross apply
(select time +',' from tablename where id=a.StaffNo and name=a.Date for xml path('')) B (alltime)

Posted 18-Feb-13 22:20pm

ssd_coolguy