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There are two things required. A Timer control, set for about 1 minute (60000 milliseconds), and some very simple math. In the timer event, all you do is get the current time, look at the minutes property and see if it is a nice even multiple of the number of minutes your user has selected.
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'mnPulse is a module level var
Static dtLastTick As Date = DateAdd(DateInterval.Minute, mnPulse * -1, Now)
If DateDiff(DateInterval.Minute, dtLastTick, Now) >= mnPulse Then
If Now.Minute Mod mnPulse = 0 Then
'Do your thing here
dtLastTick = Now
End If
End If
Hope this helps.
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srone wrote:
'mnPulse is a module level var
Static dtLastTick As Date = DateAdd(DateInterval.Minute, mnPulse * -1, Now)
If DateDiff(DateInterval.Minute, dtLastTick, Now) >= mnPulse Then
If Now.Minute Mod mnPulse = 0 Then
'Do your thing here
dtLastTick = Now
End If
End If
What's with all the extra junk in bold?? You might want to re-read to OP's requirements. YOu're making it much harder than it needs to be.
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You're correct, all he needs is
If Now.Minute Mod mnPulse = 0 Then
'Do your thing here
End If
with a timer.interval set to 60000.
If he wants the event to happen at 10:00 he will need all the rest with the interval set to 1000.
Not my first attempt at over engineering something.
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consistently using bold for junk seems like a very good idea...
Luc Pattyn [Forum Guidelines] [My Articles]
this weeks tips:
- make Visual display line numbers: Tools/Options/TextEditor/...
- show exceptions with ToString() to see all information
- before you ask a question here, search CodeProject, then Google
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Thanks for all your help and suggestions, the final code looks like this:
<code>
Sub PrintData()
Dim Interval As Integer
Dim n1 As Integer
Dim n2 As Integer
Interval = User_Log_Interval
n1 = Format(Now, "nn") 'Current Minute
n2 = Interval 'Interval
If (n1 Mod n2)= 0 Then
'Run Script
Else
'Dont Run Script
End If
End Sub</code>
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after some more testing, "If (n1 Mod n2)= 0 Then" doesnt allow the current minute to be 00, and it doesnt allow the interval to be 0 or 1, i change it to the following code and all seems well "If Int(n1 / n2) = n1 / n2 Then"
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Since the "question" you're asking is so broad, it tells me that you don't have any idea what you're talking about.
remkarggg wrote: should i be aware of the username and passwords?
This would be dictated soley by the Telnet Server you're trying to connect to. Noone here can tell you what you should be looking for. Generally, yes, the server will possibly ask you for a username and password.
remkarggg wrote: how to connect a telnet server with source code,
User a third party library, like this[^].
remkarggg wrote: how things aplly wen connecting
If you don't already understand the TCP/IP connect process, you're not going to understand it with a couple of forum posts. This is a subject that normally takes an entire set of chapters in a book to explain.
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You're best source of information on using a third party library is going to be the manufacturer of the library. I've never heard of Jscape, of this telnet library, so I can't give you a definitive answer.
You paid the money for the library, ask the people who wrote it how to use it. I'm pretty sure it came with documentation on the basics of using it.
But, in general, you add a reference to the DLL file supplying the classes you want to use. THen you import the namespaces those classes are in at the top of the code you want to use them in. For example (don't even think of copy'n'pasting this into your code):
Imports Jscape.Telnet
Now, I have no idea what the namespaces are in that library, so this code will most likely NOT work. That's what the documentation you paid for is for.
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i am using contextmenustrip in my pgm , i am not able to get the custom popup at the place user clicks , it is showing at different x,y positions And when i rt clicks on textbox it is showing the textbox default rtclick popup menu .I want to hide it . i am using like this but of nouse ..
RtClickPropertiesStrip.Show(New Point(ihorizontal, ivertical), ToolStripDropDownDirection.BelowRight) in mouseDown ifit is mouse rt click
or i use pointtoclient(cursor.position) no use ..
waiting for response
DVSRiRAM
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Why are you even using this code?? The menu already pops up where you right-click the form, so long as the form's ContextMenu property is set to the ContextMenuStrip you want it to show.
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I want to display the popup menu for the runtime contol of textbox , but it is showing both the predefined and custom defined menus . Predefined is showing at the mouse click . How to Disable this one and set the Custom defined popup menu for runtime controls . I am getting for Label . etc Only this problem is for combo box and textbox generated at runtime only using contextmenustrip in vs2005
DVSRIRAM
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OK, the answer doesn't change. Your code still has to set the ContextMenu property of the TextBox you create, just like any other property on it like Size and Location. All you have to do is assign it the menu object you created.
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Thanks Its Working ....
DVSRIRAM
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 Hi ,
How i can cut ,copy ,paste a runtime control . I Searched the net but not get the desired results .For example (It is the functionality of VS2005)
ctrl.Visible = True I used CTRL as a object type which i used for creation of controls .
I wish Your Help is Required ....
DVSRIRAM
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At runtime?? You have to implement this entire functionality yourself, using a generic Control object. Copy would set the your Control object ot the control being Copy/Cut, paste would Add this Control object to whatever container's Controls collection.
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Presently i am using contextmenustrip which is a control for showing menus when user rt clicks the mouse . I am not getting the popup at the user clicked position. i used like this inthe ctrl_mouseDown or
RtClickPropertiesStrip.Show(New Point(ihorizontal, ivertical), ToolStripDropDownDirection.BelowRight)
But of NO USE and while clicking on TExtbox it is showing their default properties . i have to overwrite those predefined and want to show custom defined popup .
Waiting for Response
DVSRIRAM
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You set the ContextMenu property of the Form to your menu. This make the menu pop up for the entire form, BUT NOT FOR THE CONTROLS ON THE FORM! You have to set the ContextMenu property on any controls on the form, like your TextBox, where you want this same menu to appear. If you want the same menu to appear for all of the controls, you'll have to set the ContextMenu property of ALL the controls on the form to your context menu.
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Respected gurus
I m working with a windows datagrid.i need two headers in my grid.
eg..
Product name
cat1 cat2 name1 name2
data data data data
data data data data
How to achieve it.
My data is coming from backend.
i need it in the windows application......
-- modified at 8:43 Thursday 20th September, 2007
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It's not supported by the old DataGrid, or by the DataGridView controls. You'd have to add this yourself, either by using cleverly placed and defined label controls above the DGV, possibly in your own UserControl, or by creating your own version of the DGV control and adding this functionality to the existing control using custom properties and painting code.
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Hi Friends..
I use a main menu control to show menu items..Now i need to show a image in menu along with some text ..Is it possible..? Can anybody give the code for it..
Regards,
Balaguru
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Yes it is possible, for this you will need to set image property of ToolStripMenuItem object.
Following is a code snippet showing this behavior-
----------------------------------------
Dim NewItem As New ToolStripMenuItem
NewItem.Text = "New Item"
NewItem.Image = Image.FromFile("C:\img11.jpg")
Me.OpenToolStripMenuItem.DropDownItems.Add(NewItem)
------------------------------------------
I hope this helps .
-Dave.
Dave Traister,
ComponentOne LLC.
www.componentone.com
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Hi Dave,
Is ToolStripMenuItem a tool present in the toolbar..?
How to get it in the toolbar and use..?
Regards,
Balaguru
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If you are using Visual Studio 2005, you should have MenuStrip item in Toolbox, which is a ToolStripMenuItem object.
However it seems that you are using Visual Studio 2003 and .Net framework 1.x.
In this case you are correct we do not have any direct way to add image into the menu item, because any Image or Icon property has not been provided for the MainMenu.
However you may still have an image in menu by drawing whole menu item using custom code.
For this you will need to first set OwnerDraw property of MainMenu control to True.
This allows you to take control of control rendering. Then under DrawItem event you may have your custom code for drawing.
You may check following article which provides good information about the whole process-
http://www.codeproject.com/cs/menu/menuimage.asp
I hope this helps .
-Dave.
Dave Traister,
ComponentOne LLC.
www.componentone.com
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Hello friends ,
It is possible to create window netmeeting type application in
vb.net if yes how ? thanks in advance .
manu
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